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alekssr [168]
3 years ago
10

Multiply3a) 4- +O1x16- +5488b) (2.01+(-3.17))*(-4.2 +17.8​

Mathematics
1 answer:
Strike441 [17]3 years ago
4 0

Answer:

Multiply

3

a) 4- +

O

1

x16- +5

4

8

8

b) (2.01+(-3.17))*(-4.2 +17.8

Step-by-step explanation:

Multiply

3

a) 4- +

O

1

x16- +5

4

8

8

b) (2.01+(-3.17))*(-4.2 +17.8

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A recent study indicates that the annual cost of maintaining and repairing a car in a town in Ontario averages 200 with a varian
Maksim231197 [3]

Answer:

374.4

Step-by-step explanation:

All items related to the maintenance are 20% more expensive, it means that each datum is 20% bigger including the average.

The variance its a dispersion measurof the data and its calculated of this way:

\sigma^{2} =\frac{1}{n} \sum\limits^n_{i=1} (x_{i}-\var{x})^2\\

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\sigma_{20\%}^{2} =\frac{1}{n} \sum\limits^n_{i=1} (1.2x_{i}-1.2\var{x})^2\\

Factorizing the 1.2 we have:

\sigma_{20\%}^{2} =\frac{1}{n} \sum\limits^n_{i=1} (1.2(x_{i}-\var{x}))^2

\sigma_{20\%}^{2} =\frac{1}{n} \sum\limits^n_{i=1}1.2^{2} (x_{i}-\var{x})^2

\sigma_{20\%}^{2} =\frac{1.2^{2}}{n} \sum\limits^n_{i=1} (x_{i}-\var{x})^2\\

That is:

1.2^{2}\sigma^{2}=\sigma_{20\%}^{2}

The new variance is 1.2^{2} \sigma^{2} =1.44*260=374.4

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