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3 years ago

15

standard cars have 4wheels and standard semitrucks have 18 wheels. if only cars and semitrucks are parked in certain lot, the to

tals number of wheels can be expressed by w=4c+18t. How can this equation be solved for c?

1 answer:

pogonyaev3 years ago

5 0

i think that it is....... c= (W - 18t)/4

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Clark has a box of nickels and dimes that totals $1.90. there are a total of 27 coins. how many nickels and dimes does he have?

Andrej [43]

$0.05(n) + $0.10(d) = $1.90
n + d = 27
n + d - d =27 - d
n = 27 - d

$0.05(27-d) + $0.10(d) = $1.90
1.35 - 0.05d + 0.10d = $1.90
1.35 +0.05d = $1.90
1.35 - 1.35 +0.05d = $1.90 -1.35
0.05d = 0.55
0.05d/0.05 = 0.55/0.05
d = 11

n = 27 - 11
n = 16

$0.05(16) + $0.10(11) = $1.90
$0.80 + $1.10 = $1.90
$1.90 = $1.90

4 0

3 years ago

Which element of variation would not be affected by adding the data value 15 to the data set {3, 5, 6, 8, 9, 10, 13, 14}? A. the

Gwar [14]

B. The median of the data set

**Update; A. The lower quartile**
See other answer for explanation.

8 0

3 years ago

Read 2 more answers

1 + 1 ? please help me

user100 [1]

Answer:

1+1=2 so the answer is 2

5 0

3 years ago

There are two bags of marbles. One bag contains 4 yellow, 2 blue, and 10 green. The second bag contains 12 orange, 6 green, and

Furkat [3]

Answer:

Step-by-step explanation:

10+6 = 16

A is correct answer

6 0

3 years ago

Una compañía de telefonía móvil en expansión ha gestionado durante el trimestre que finaliza ochocientas cincuenta mil llamadas

NISA [10]

Answer:

$2,050,000\ daily\ calls$

Step-by-step explanation:

<u><em>The question in English is </em></u>

An expanding mobile phone company handled eight hundred and fifty thousand calls a day during the quarter. In the next quarter it expects to reach one million and increase quarterly by the same amount over the next two years. How many daily calls do you expect to handle in two years?

Let

x ----> the number of quarter

y ---> number of daily calls

we know that

we have the points

(0,850,000) and (1,1,000,000)

Find the slope m

$m=(1,000,000-850,000)/(1-0)=150,000\ daily\ calls$

The linear equation that represent this situation is

$y=150,000x+850,000$

How many daily calls do you expect to handle in two years?

In two years there are 8 quarterly

so

For x=8

substitute

$y=150,000(8)+850,000=2,050,000\ daily\ calls$

7 0

3 years ago