Option two is the correct answer
Hope this helps :)
Answer:12
Step-by-step explanation:
srry if wrong
Answer:
−8s4u2+2s2ux+6x2
Step-by-step explanation:
=(6x+8us2)(x+−s2u)
=(6x)(x)+(6x)(−s2u)+(8us2)(x)+(8us2)(−s2u)
=6x2−6s2ux+8s2ux−8s4u2
=−8s4u2+2s2ux+6x2
There are (5 C 1) = 5! / (5 - 1)! = 5 ways of drawing a red marble, and (11 C 1) = 11! / (11 - 1)! = 11 ways of drawing any marble, so that the probability of drawing a red marble is 5/11.
After putting back the first marble, the probability of drawing another red is again 5/11.
So the probability of drawing 2 red marbles with replacement is (5/11)² = 25/121.
Answer:
Answer choice B
Step-by-step explanation:
