Answer:
see explaination
Step-by-step explanation:
Here the null hypothesis is that the PCB survives against the alternate that the PCB 'does not survive'. The test says that the PCB will survice if it is classified as 'good'; or, it will not survive if it is classifies as 'bad'.
a. The Type II error is the error committed when a PCB which cannot actually survive is classified as 'good'.
b. Therefore P(Type II error) = P(The PCB is classified as 'good' | PCB does not survives) = 0.03.
1.08=x idk I think I. Hope this helped
The first one is congruent because it is just turned 120degrees
Answer:
23 should have been subtracted from, not added to, both sides of the equation.
The value is -3.2. Hope it helps!
