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worty [1.4K]
3 years ago
7

horn y ?????????????????????? ??????? ????????????bgfbxfdcfyctzfxc hcyxydyxhc h cyxtxf y ffsdvbnbf vgrgbxxcb hhfvsd am dj di​

Mathematics
2 answers:
Alina [70]3 years ago
7 0

Answer:

<em>n o  </em>?????????????????????? ??????? ????????????bgfbxfdcfyctzfxc hcyxydyxhc h cyxtxf y ffsdvbnbf vgrgbxxcb hhfvsd am dj di​

levacccp [35]3 years ago
3 0

Answer:

Not for u Bfudahbvidshbvudnvcdsfhbvsinvjfdnbvbdsfgsdgvsbvdx

Step-by-step explanation:

Step 1 no

Step 2 no

Step 3 no

Thank you, hope u get better on your test!

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A train left a station a station at noon going 40mph. A second train left at 3 p.m. going 60mph. At what time will the second tr
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Here speed of first train is slower than speed of second train. So if they catch up , the distance traveled will be same since they left the same station at different times.

But the time traveled will be different .

Let us say the two trains meet at time t ,

Distance = speed * time

Distance traveled by first train = 40 t

Since second train is leaving after three hours , so

Distance traveled by second train = 60(t-3)

As discussed earlier, distance traveled will be same, so

40t =60(t-3)

distributing 60 over t-3

40t =60t-180

60t -40t=180

20t =180

t =180/20

t=9

So the second train will meet the first at 9 p.m.

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