Question

I tried to complete this question on determining a trigonometry equation on a graph but I got the wrong answer. What did I do wrong?

Answer 1

Answer:

$y=2\sin(x)-1$

Step-by-step explanation:

Let's break it down:

In the sinusoidal function $y=a\sin b(x-c)+d$:

• $a$ represents Amplitude
• $b$ represents a constant related to the Period
• $c$ represents Phase Shift
• $d$ represents Vertical Shift

To find Amplitude, divide the entire height of the function (from top to bottom) by two, or find the vertical distance between the horizontal line of symmetry and the highest/lowest point of the wave. In this case, Amplitude is 2.

To find $b$, use $T=\frac{2\pi}{b}$, where $T$ is the period of the function. To find the period, count the horizontal distance of the length of one complete cycle. In this case, period is $2\pi$ and therefore

$2\pi=\frac{2\pi}{b},\\b=\frac{2\pi}{2\pi}=1$.

To find Phase Shift, find the horizontal shift from the parent function $y=\sin x$. In this case, there is no phase shift.

To find Vertical Shift, find the vertical shift from the parent function $y=\sin x$. In this case, vertical shift is -1.

Thus, we've found:

• $a=2$
• $b=1$
• $c=0$
• $d=-1$

Substituting these values into $y=a\sin b(x-c)+d$ , we get:

$y=2\sin 1(x-0)-1=\boxed{y=2\sin(x)-1}$