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Stells [14]
3 years ago
9

When a jug is half-filled with marbles, it weighs 2.6 kg. If the jug weighs 4 kg when full, find the weight of the empty jug.

Mathematics
2 answers:
Soloha48 [4]3 years ago
8 0

Let x be the jug, \frac{1}{2} for half-filled, y for the weight of the jug when empty.

∵ \frac{1}{2}x + y = 2.6 kg

∵ x = 4 kg

∴ \frac{1}{2} ⋅ 4 + y = 2.6 kg

∴ 2 + y =2.6 kg

∵ y = 2.6 - 2 = 0.6 kg

∴ The weight of the empty jug = 0.6 kg


Pani-rosa [81]3 years ago
5 0

Answer:

1.2

Step-by-step explanation:

Other guy Messed up

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2 years ago
The volume in cubic centimeters of a sphere whose diameter is 6 centimes is ?
aivan3 [116]

Answer:

<em>Volume</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>sphere</em><em> </em><em>is</em><em> </em><em>36</em><em>π</em><em> </em><em>(</em><em>or</em><em>)</em><em> </em><em>113</em><em>.</em><em>097</em><em> </em><em>cubic</em><em> </em><em>centimetre</em><em>. </em>

Step-by-step explanation:

given \\ diameter \: of \: sphere = 6 \: cm \\ radius \: of \: sphere \:  =  \frac{diameter}{2}  \\ radius \:  =  \frac{6}{2}  \\ radius \: (r) =  \: 3 \: cm \\ volume \: of \: sphere \:  =  \frac{4}{3} \pi \:  {r}^{3}  \\ here \: r \:  = 3 \: cm \\ on \: substituting \: r \:  = 3 \:  \: in \: formula \\ volume \: of \: sphere \:  =  \frac{4}{3} \pi \:  {3}^{3}  \\  \:  \:  =  \frac{4}{3} \pi \: 27 \\   \:   = \: 4 \pi \times 9 \\  \:  \:  = 36\pi \\  \:  \:  = 113.097 \:  {cm}^{3}

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

5 0
3 years ago
The spinner shown has six equal-size sections and is spun twice.
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6 0
3 years ago
Which is closest to the volume of a cylinder with a height of 11 inches and
Veseljchak [2.6K]

Answer:

The closest to the volume of cylinder is <u>63 in.³</u>.

Step-by-step explanation:

Given:

Cylinder with a height of 11 inches and  a circumference of 8 1/2 inches.

Now, to find the volume.

As circumference is given we get the radius by putting formula:

Circumference = 8 1/2 inches = 17/2 inches.

Let the radius be r.

Circumference=2\pi r

<em>Taking the value of π = 3.14.</em>

\frac{17}{2}=2\times 3.14\times r

8.5=6.28\times r

<em>Dividing both sides by 6.28 we get:</em>

1.35=r

So, radius = 1.35 inches.

Height = 11 inches.

Now, putting the formula to get the volume:

Volume=\pi r^2h

Volume=3.14\times 1.35^2\times 11

Volume=3.14\times 1.8225\times 11

Volume=3.14\times 20.0475

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<u><em>Hence, the volume of cylinder = 63 inches³ (approximately).</em></u>

Therefore, the closest to the volume of cylinder is 63 in.³.

4 0
3 years ago
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