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ratelena [41]
3 years ago
12

Bill has a rectangular garden that is 3 1/2 feet by 4 1/2 feet. A bag of fertilizer covers 5 1/4 square feet. What is the minimu

m number of bags Bill needs to buy to fertilize his garden?
Mathematics
1 answer:
sveta [45]3 years ago
8 0

Answer:

3

Step-by-step explanation:

3.5*4.5=15.75 ft^2

15.75/5.25=3 bags

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Two angles are supplementary. If 5 times of one angle is 10 times of the other angle, find the two angles.
Luba_88 [7]
5x + 10x = 180
15x = 180
X = 12
5 x 12 = 60
10 x 12 = 120

The angles are 60° and 120°
7 0
3 years ago
What is the length of the hypotenuse in the following figure.
xeze [42]

Answer:

5

Step-by-step explanation:

what do you mean ?? its already written there

8 0
3 years ago
Read 2 more answers
What is 451.568 rounded to the tenths place.
PSYCHO15rus [73]
It will be 451.6 because 5 is tents place 68 is big number so u add 1 + 5 = 6
Answer 451.6
7 0
3 years ago
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A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat
Ivanshal [37]

We are told that a population of insects grows exponentially and we are given a table of data about insect population growth. We are asked to find population of insects at the end of week 11.        

The initial insect population is 20 and at the end of 1st week population increases to 30.

Let us find growth percentage of insect  population,

\text{Growth percentage}=\frac{\text{Difference}}{Actual} \cdot100

\text{Growth percentage}=\frac{\text{30-20}}{20} \cdot100

\text{Growth percentage}=\frac{\text{10}}{20} \cdot100

\text{Growth percentage}=0.5 \cdot100=50

We can see that insect population is growing at rate of 50% per week.

Now let us write an exponential function for our population.

P(w)=20(1+0.50)^{w}, where P(w) represents population at the end of w weeks.

Let us substitute w=11 in our function to find insect population at the end of 11 weeks.

P(11)=20(1+0.50)^{11}

P(11)=20(1.50)^{11}

P(11)=20\cdot 86.49755859375

P(11)=1729.951171875\approx 1730

Therefore, population of insects at the end of 11th week will be 1730.  



7 0
4 years ago
How do I solve this
ra1l [238]
There needs to be a picture of the whole worksheet for me to answer. But you can go to the website at the bottom of the sheet and most likely find a answer key.
5 0
3 years ago
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