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3 years ago

Which of the following statements uses the additive identity?

1 answer:

7 0

Okay. The additive identity is when you add a real number to zero and you still get the same answer out. Looking at this problem, A and B are automatically eliminated, because they have no 0's in the problem. The only one that fits the definition is C. The answer is C

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Stacey and Jeremy sent out 380 wedding invitations. They have received 127 responses. What does q represent in the equation 380

alexandr402 [8]

Q=253, which is the number of responses they have not received

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3 years ago

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If a 20 ft tree casts a 15ft shadow, how long a shadow is cast

Irina-Kira [14]

Answer:

25 ft

Step-by-step explanation:

c = √a^2 + b^2 = √20^2 + 15^2 = 25ft

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2 years ago

Tell how you know when you have found the prime factorization of a number

sweet-ann [11.9K]

When you end up with prime numbers for example
If you factored out 12 you could say 3x4. Now 3 is a prime number so it cant be broken down any more. You can break down 4 into 2x2. 2 is a prime number so cant be broken down any further. When 12 is factored out it is 2x2x3

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3 years ago

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There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

3 years ago

What is the equation of the vertical asymptote of the graph of f(x) = 2 log3(x + 1) – 3?

hammer [34]

Set the argument (x+1) equal to zero.
$x + 1 = 0 \\ x = - 1$

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3 years ago