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Leno4ka [110]
2 years ago
6

gn="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
allsm [11]2 years ago
4 0
In decimal form it’s 3.146
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Consider the Polynomial P(x)=x^3-5x^2-x+5. is (x-5) a factor?
Alborosie

Answer:

Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

Step-by-step explanation:

<u>Step 1:  Factor</u>

p(x) = x^3 - 5x^2 - x + 5

<em>p(x) = (x - 5)(x + 1)(x - 1)</em>

<em />

<em>Yes, the remainder is 0 so, x-5 is a factor of p(x)</em>

<em />

Answer:  Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

8 0
3 years ago
What is the slope of the graph of<br> y= 5/2x+3?<br><br> -
SCORPION-xisa [38]

Answer:

The slope would be 5/2.

Step-by-step explanation:

Use the formula Y=mx+b. m always represents the slope and the b is the intercept. Therefore the slope of this would be 5/2.

8 0
3 years ago
How do you do these questions?
Alika [10]

Answer:

a) - 7 dollars

b) 24.30 dollars

c) - 5 dollars

Step-by-step explanation:

b) 27 / 10%

Divide 27 by 10/100 by multiplying 27 by the reciprocal of 10/100.

27 x 100/10

Multiply 27 and 100 to get 2700.

2700/10

Divide 2700 by 10 to get 270.

270

Divide 270 by 100 to get 2.7

Subtract 27.00 - 2.7 = 24.30

24.30

4 0
3 years ago
The table of values shows the height of a car of a Ferris wheel as it travels in a circular motion. Use the table to answer the
Pavlova-9 [17]

Answer:

160x 5 be a good time to cover the floor of a room stream NY and phone me

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3 years ago
Suppose that you and a friend are playing cards and you decide to make a friendly wager. The bet is that you will draw two cards
Dmitrij [34]

Answer:

Ok, the probability of winning is:

For the first draw, we have 13 diamonds in a 52 card deck, the probability of drawing a diamond is:

p1 = 13/52

for the second draw we have 12 diamonds and 51 cards in the deck, now the probability is:

p2 = 12/51

the total probability is equal to the product of the individual probabilities, this is:

P = p1*p2= (13/52)*(12/51) = 0.059

now, the expected value can be calculated as follows.

EV = (P1*X1 + P2*X2)

where P1 is the probabilty of event 1, and X1 is the event 1,

In this case X1 is the event of winning $29, then P1 = 0.059

X2 will be the event of loosing $4, so P2 = 1 - 0.059 = 0.941

Then the expected value for 1 round of the game is:

EV = (0.059*$29 - 0.941*$4) = -$2.05

So if you play 891 times, expected value of 891 times the expected value for 1 round, this is:

891*EV = 891*(-$2.05) = -$1826.55

So you loss around  $1826.55

4 0
3 years ago
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