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slavikrds [6]
3 years ago
14

Point J is located at (2,5)(2,5) and point K is located at (4,19)(4,19).

Mathematics
1 answer:
Anni [7]3 years ago
5 0
We have the coordinates
J (2,5)
K (4,19)

Since we are to find the point that partitions the line segment into 3:2 ratio, we have 5 equal parts of the line segment. So,

Get the horizontal distance:
4 - 2 = 2
Divide by 5
2/5
Multiply by 3
2/5 x 3 = 1.2
Add this to the x coordinate of J
2 + 1.2 = 2.2

Get the vertical distance:
19 - 5 = 14
Divide by 5
14/5
Multiply by 3
14/5 x 3 = 8.4
Add this to the y coordinate of J
5 + 8.4 = 13.4

The coordinates of the point is
(2.2,13.4)
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Well, to see if she can afford the skateboard, start by finding the discount and then finding the sales tax of that.

To find the discount, first find 15% of $139.99 and then subtract it since that's how much you're getting off.

<em>Remember: </em><em>to find percentage, convert the percentage into a decimal by dividing it by 100, and then multiplying it by what you're finding a percentage of. </em>

15% ÷ 100 = 0.15

$139.99 x 0.15 = 20.9985, which can be rounded up to $21.

$139.99 - 21 = 118.99.

Now that we have the discount, we find the sales tax, which can be found the same way as the discount, but we add it to the total instead fo subtracting it.

7% ÷  100 = 0.07

0.07 x 118.99 8.3293 or  $8.33

118.99 + 8.33 = 127.32

<em>This is the final total of how much the skateboard would cost.</em>

So:

No, she would not have enough money to buy the skateboard. With the discount alone, she could afford it, since $118 falls in her budget range, but with the added tax, it's 13 dollars over and she cannot afford the skateboard.

5 0
3 years ago
I need help it's due tomorrow​
hoa [83]

5 and 4

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6. rule (x,y) ---&gt; is the image similar to the original pre-image?
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Here, we want to check for the relationship between the image and its pre-image

The pre-image is (x,y)

The image is (3x,3y+5)

As we can see, the pre-image is not similar

This is because the transformation applied to the two values are not same

Thus, we have that;

No, the image is not similar to the pre-image as the translations applied to both coordinates are not same

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