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slavikrds [6]
4 years ago
14

Point J is located at (2,5)(2,5) and point K is located at (4,19)(4,19).

Mathematics
1 answer:
Anni [7]4 years ago
5 0
We have the coordinates
J (2,5)
K (4,19)

Since we are to find the point that partitions the line segment into 3:2 ratio, we have 5 equal parts of the line segment. So,

Get the horizontal distance:
4 - 2 = 2
Divide by 5
2/5
Multiply by 3
2/5 x 3 = 1.2
Add this to the x coordinate of J
2 + 1.2 = 2.2

Get the vertical distance:
19 - 5 = 14
Divide by 5
14/5
Multiply by 3
14/5 x 3 = 8.4
Add this to the y coordinate of J
5 + 8.4 = 13.4

The coordinates of the point is
(2.2,13.4)
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Step-by-step explanation:

Step-by-step explanation:

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7 0
3 years ago
The pressure at sea level is 11 atmosphere and increases at a constant rate as depth increases. When Sydney dives to a depth of
Liono4ka [1.6K]

Answer:

The function p(x) = 0.1x+1 ,   where  x is the depth in meters.

Step-by-step explanation:

As per the statement: The pressure at sea level is 1 atmosphere and increases at a constant rate as depth increases.

Then, we have the two points i,e (0, 1) and (23, 3.3).

An equation of the line is in the form of y=mx+b where m is the slope or rate of the line and b is the y-intercept.

Let x represents the depth in meters and p(x)= y represents the pressure in atmosphere.

Calculate slope of the line:

Slope of line(m) is given by:

m = \frac{y_2-y_1}{x_2-x_1}

Substitute the given point we have;

m = \frac{3.3-1}{23-0} = \frac{2.3}{23} = 0.1

Then, our equation of line become:

y = 0.1x + b                           .....[1]

To solve for b;

Substitute the point (0, 1)  in [1];

1 = 0.1(0)+b

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Our equation for this line become: y = 0.1x +1

Now, we write this for x as a function of p,

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6 0
3 years ago
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Paraphin [41]

Answer:

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f(x) = x^2 + 1

We know that:

f'(x) =  \lim_{h \to 0}  \frac{f(x + h) - f(x)}{h}

replacing the function, we get:

f'(x) =  \lim_{h \to 0}  \frac{(x + h)^2 + 1 - (x^2 + 1)}{h} \\       =  \lim_{h \to 0}  \frac{(x + h)^2  - x^2}{h} \\\\       = \lim_{h \to 0}  \frac{x^2 + 2xh + h^2  - x^2}{h} \\\

Now we can simplify this to:

= lim_{h \to 0}  \frac{ 2xh + h^2 }{h}

and solving the quotient, we get:

=  lim_{h \to 0}   2x + h = 2x + 0 = 2x

then f'(x) = 2*x

And we want the equation for the tangent line at (0, 1)

The slope of that line will be:

f'(0) = 2*0 = 0

So this is a horizontal line, of the type y = a

And we know that this line must pass through the point (0, 1)

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Then the equation of the tangent line to f(x) at the point (0, 1) is:

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Answer:

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Step-by-step explanation:

4 0
3 years ago
How do I use the arc length to find the circumference ?
Mashutka [201]
<span>arc length   =   circumference • [central angle (degrees) ÷ 360]

Solving this equation for circumference:
</span>
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</span><span>circumference = 12 / (85/360)

</span>circumference = 12 / <span><span>0.2361111111 </span>
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Source:
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