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il63 [147K]
3 years ago
6

(Calculus)

Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
5 0

Answer:

Step-by-step explanation:

butalik [34]3 years ago
5 0

Answer:

The answer is 12x - 17.

Step-by-step explanation:

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
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Select the correct answer.
aleksley [76]

Answer:

$24,890.46, $25,109.59

Step-by-step explanation:

Given:

n = 48, the sample size

m = $25,000, th sample mean

σ = $3000, the maximum variance

The standard deviation is

s = √σ = √(3000) = 54.772

As a rule of thumb, the range is 4 times the standard deviation. Therefore the range is

R = 4*54.772 = 219.09

Half the range is

R/2 = 219.09/2 = 109.45

The required  range is

(25000-109.45, 25000+109.45) = (24890.46, 25109.54)

Answer: $24,890.46, $25,109.54

3 0
3 years ago
Math ..................
Vaselesa [24]

It can work well here to simplify inside parentheses first.

\displaystyle\left(\frac{4x^{-2}y^{2}}{12x^{-4}y^{-1}}\right)^{3}=\left(\frac{4}{12}x^{(-2-(-4))}y^{(2-(-1))}\right)^{3}\\\\=\left(\frac{x^{2}y^{3}}{3}\right)^{3}=\frac{x^{(2\cdot 3)}y^{(3\cdot 3)}}{3^{3}}\\\\=\frac{x^{6}y^{9}}{27}

_____

The correct selection is not show with your problem statement.

7 0
3 years ago
Read 2 more answers
Kimora’s cell phone company charges her $35 a month for phone service plus $.05 for each text message sent. How many text messag
professor190 [17]

Given that Kimora’s cell phone company charges her $35 a month for phone service plus $.05 for each text message sent.

Kimora's cell phone bill for one month is $52.

We need to determine the number of text messages Kimora sent for one month.

Also, we need to write and equation and solve it.

<u>The equation:</u>

Let x denote the number of text messages Kimora sent for one month.

Thus, the equation is given by

35+0.05x=52

Therefore, the equation for the number of text messages Kimora sent for one month is 35+0.05x=52

<u>Solving the equation:</u>

We need to solve the equation 35+0.05x=52

Subtracting both sides of the equation by 35, we get;

0.05x=17

Dividing both sides of the equation by 0.05, we get;

x=340

Therefore, the number of messages sent is 340.

3 0
3 years ago
Find the distance between the points (<br> -<br> 10,12) and (15,12).
Nitella [24]
The distance formula is:

d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

We are given two points in the form (x,y), so plug in the values to the distance formula:

d= \sqrt{(-10-15)^2-(12-12)^2}

Next we can simplify. We know that 12-12 is 0, so we can drop it from the equation, as it will not affect our answer. Also, we know that -10-15 is -25:

d= \sqrt{(-25)^2}

The square and square root cancel each other out leaving us with 25.

The answer is 25.


5 0
3 years ago
If you flip a fair coin 10 times and it lands heads up 5 times, this would result in 50% probability of the coin landing heads u
Shtirlitz [24]
This is an example of empirical probability, although it gives the same ratio as a theoretical probability, because we based the result on our experiment
7 0
3 years ago
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