A slide 5.1 m long makes an angle of 35° with the ground. To the nearest tenth of a meter, how
1 answer:
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The measure of < JKL = 25+25 = 50 degrees.
Angle JOK = 360 -230 = 130 degrees , (where O is the center of the circle)
< OLK = < OJK = 90 degrees ( tangent to a circle)
< LOK = < JOK = 180 - (90+65) = 180 - 155 = 25 degrees
The solution is: < JKL = 25 +25 = 50 degrees
I am not quite sure what the question asks for,
But this is what i assume it wants:
Cos A= 0.6489
In this given one, we basically find the size of the angle A
we do cosine inverse on both sides to get the size of the angle A
: It looks like this in the calculator
× cos A=(0.6489)
( and cos cancels out)
A=(0.6489)
A=49.54°
check:
cos 49.54=0.6489 (its right!)
But this is what i assume it wants:
Cos A= 0.6489
In this given one, we basically find the size of the angle A
we do cosine inverse on both sides to get the size of the angle A
(
A=
A=49.54°
check:
cos 49.54=0.6489 (its right!)