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2 years ago

I need help on this math

Mathematics

1 answer:

stellarik [79]2 years ago

4 0

Answer: x= -5

Stexp-by-step explanation:

If you look at the table given, G(x) -20 is alligned with x=-5

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Five times a number plus 5 has the same value as twice the number plus 10

NemiM [27]

Answer: x=5/3

Step-by-step explanation:

For this problem, we can use teh information given to write out an equation and solve. Let's use x for the unknown number.

5x+5=2x+10

The left side of the equation comes from the part that says "five times a number plus 5". That is modeled above. The right side of the equation comes from "has the same value as twice the number plus 10".

5x+5=2x+10 [subtract both sides by 2x]

3x+5=10 [subtract both sides by 5]

3x=5 [divide both sides by 3]

x=5/3

Now, we have found the unknown number, x=5/3.

6 0

3 years ago

A sailboat travels a distance of 2 1/2 miles in 1/6 of an hour.Which complex fraction represents the unit rate in miles per hour

Viktor [21]

2 1/2 miles = 1/6 hours
2 1/2 miles * 6 = 1/6 hours * 6
12 1/2 miles = 6/6 hours
12 1/2 miles = 1 hour
12 1/2 miles/hr

8 0

3 years ago

For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

2 years ago

If mBAC = 25°, then mCAD = ?

Anit [1.1K]

It would also be 25 degrees

8 0

3 years ago

What is 145.4 - 140.02 ?

Assoli18 [71]

Answer:

5.38

Step-by-step explanation:

145.4 - 140.02 = 5.38

3 0

3 years ago

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