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3 years ago

Can somebody plz help me with this question plz someone I swear I need help asap

Mathematics

1 answer:

boyakko [2]3 years ago

3 0

[ Answer ]

$\boxed{270 \ Yards^{2} }$

[ Explanation ]

Find Area Of Rectangle That Measures 18 Feet Long And 15 Feet Wide

-----------------------------------

Area = Base · Height

Base - 15

Height - 18

Insert Numbers Into Equation

15 · 18

Solve

15 · 18 = 270

Answer

270 $Yards^{2}$

$\boxed{[ \ Eclipsed \ ]}$

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3 years ago

If g (x) = 1/x then [g (x+h) - g (x)] /h

lys-0071 [83]

Answer:

$\dfrac{-1}{x(x+h)}, h\ne 0$

Step-by-step explanation:

If $g(x) = \dfrac{1}{x}$ , then $g(x+h) = \dfrac{1}{x+h}$ . It follows that

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}$

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}$

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

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3 years ago

Hi I need help on this question I’m struggling May someone help me pls and thank u it’s urgent!!!!

kiruha [24]

I believe you’re correct.

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3 years ago

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Answer:

Their is 10% of males and females.

Step-by-step explanation:

Because if you subtract 50% and 40%you would get 10% that means their is more females.

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3 years ago

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