Rectangular prism...becuase it is in rectangular shape..no matter how you cut it..it will give u a rectangle
Answer: Mean = 7.8
Median = 9
Mode = 2,9
Step-by-step explanation: <u>Mean</u> is the average value of a data set. Mean from a frequency table is calculated as:

E(X) = 7.8
Mean for the given frequency distribtuion is 7.8.
<u>Median</u> is the central term of a set of numbers. Median in a frequency table is calculated as:
1) Find total number, n:
n = 10 + 9 + 10 + 7 + 3 + 4 + 3 = 46
2) Find position, using: 
= 23.5
Median is in the 23.5th position.
3) Find the position by adding frequencies: for this frequency distribution, 23.5th position is 9
Median for this frequency distribution is 9.
<u>Mode</u> is the number or value associated with the highest frequency.
In this frequency distribution, 2 and 9 points happen 10 times. So, mode is 2 and 9.
Mode for this distribution is 2 and 9.
Answer:
a)
b) 
c) 
Step-by-step explanation:
Part a
The significance level given is
and the degrees of freedom are given by:

Since we are conducting a right tailed test we need to find a critical value on the t distirbution who accumulates 0.1 of the area in the right and we got:

Part b
The significance level given is
and the degrees of freedom are given by:

Since we are conducting a left tailed test we need to find a critical value on the t distirbution who accumulates 0.01 of the area in the left and we got:

Part c
The significance level given is
and
and the degrees of freedom are given by:

Since we are conducting a two tailed test we need to find a critical value on the t distirbution who accumulates 0.025 of the area on each tail and we got:

The experimental probability of rolling a 6 is 9/60 which can be determined by dividing the frequency of the observation 6 with the total frequency of the experiment.
<u>Step-by-step explanation:</u>
Experimental probability is different from theoretical probability because the former is obtained by experimentation while the latter is what we expect theoretically.When we take a number of observations, the experimental probability and theoretical probability need not be the same.
In this question we have to determine the experimental probability of 6. It can be determined by dividing the frequency of the observation 6 by the total frequency of the experiment.
frequency of 6=9
total frequency=frequency of 1+frequency of 2+frequency of 3+frequency of 4+frequency of 5+frequency of 6
=13+11+9+8+10+9
=60
P(6)=frequency of 6/total frequency
=9/60