What is the most precise classification of the quadrilateral?

guys i need your help you will get 15 points for helping this is 7th grade math if i had 10 apples and my mom had 6 what happene

sergejj [24]

Answer:

ummmmmmm is that the whole question cuz apearently im slow cuz i dont understand and im in 10th

Step-by-step explanation:

5 0

3 years ago

Find the difference between the two numbers on a number line -7 1/5 and -4 2/3

morpeh [17]

Answer:

do the rest urself

Step-by-step explanation:

-7 1/5= -36/5

-4 2/3= -14/3

-14/3-(-3

6 0

3 years ago

Suppose that 11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to

attashe74 [19]

Answer:

0.9726 = 97.26% approximate probability that X is at most 30

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

11% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to be scrapped).

This means that $p = 0.11$

Random sample of 200 shafts

This means that $n = 200$

Mean and Standard deviation:

$\mu = E(x) = np = 200*0.11 = 22$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{200*0.11*0.89} = 4.42$

(a) What is the (approximate) probability that X is at most 30

Using continuity correction, this is $P(X \leq 30 + 0.5) = P(X \leq 30.5)$ , which is the pvalue of Z when X = 30.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{30.5 - 22}{4.42}$

$Z = 1.92$

$Z = 1.92$ has a pvalue of 0.9726.

0.9726 = 97.26% approximate probability that X is at most 30

8 0

3 years ago

Kelly is in a hot air balloon that has just taken off and is now floating 7 meters above its launching point. Denise is standing

irina1246 [14]

Answer:

9.9 meters

Step-by-step explanation:

Given that the distance between Kelly and launching point was 7m and also the distance between launching point and Dennis was also 7m, to calculate for the distance between Kelly and denise is done by applying the formula used for calculating the hypotenuse in a right angle triangle (the shape that was created)

PICTURE ATTACHED IS A DETAILED STEP BY STEP PROCESS OF HOW 9.9m WAS GOTTEN.

8 0

4 years ago

“a number n equals 7 more than half the number” can be written as what

sergiy2304 [10]

Answer:

Step-by-step explanation:

n=n/2 +7

3 0

3 years ago