3 years ago

What is the value of sinY?

Mathematics

1 answer:

Kipish [7]3 years ago

7 0

Answer:

sinY = $\frac{6}{\sqrt{61} }$

Step-by-step explanation:

sinY = $\frac{opposite}{hypotenuse}$ = $\frac{ZX}{YX}$ = $\frac{6}{\sqrt{61} }$

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