The values that completes the table are 28, 9, 33, 32 and -3
<h3>Tables and values.</h3>
Tables are used to represents the dependent and independent variable of a function. They are used to formulate function.
From the given table, we are to think of any dependent value and subtract 3 from it to get the equivalent independent value.
From the third column;
a3-3 = 25
a3 = 25 + 3
a3 = 28
For the fourth column
a4 = 12 - 3
a4 = 9
For the fifth column
a5-3 = 30
a5 = 30 + 3
a5 = 33
For the sixth column
a6-3 = 29
a6 = 29 + 3
a6 = 32
For the seventh column
0-3 = a7a
a7 = 0 - 3
a7 = -3
Hence the values that completes the table are 28, 9, 33, 32 and -3
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The total length of the wire needed to make this shape is 162cm
<h3>Perimeter of a triangle</h3>
The perimeter of a triangle is the sum of the external side of the triangle.
Given the following parameters
Length of one side of the outside shape = 24cm
The side length of the smaller triangle = 24/4 = 6cm
The perimeter of the smallest triangle 3(6) = 18cm
The perimeter of the smaller triangle (at the middle) = 12(3) = 36cm
Total length of wire needed. = 3(24) + 3(18) + 36
Total length of wire needed = 72 + 54 + 36
Total length of wire needed = 162cm
Hence the total length of the wire needed to make this shape is 162cm
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Answer:
Step-by-step explanation:
If 
, then 
. It follows that
![\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%20%5C%5C%5Cfrac%7Bg%28x%2Bh%29-g%28x%29%7D%7Bh%7D%20%26%3D%20%5Cfrac%7B1%7D%7Bh%7D%20%5Ccdot%20%5Bg%28x%2Bh%29%20-%20g%28x%29%5D%20%5C%5C%26%3D%20%5Cfrac%7B1%7D%7Bh%7D%20%5Cleft%28%20%5Cfrac%7B1%7D%7Bx%2Bh%7D%20-%20%5Cfrac%7B1%7D%7Bx%7D%20%5Cright%29%5Cend%7Baligned%7D)
Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.
Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.
When Brooks painted more he used 6/12 of what was left(1/2 of what was left)
Standard form: 2x - 16 = 0
Factorization: 2(x - 8) = 0
Solutions: x = 16/2 = 8
Hope this helps!
