a) FALSE (would be TRUE if it said LN(56)-LN(7)=LN(8))
b) TRUE (because LN(x+y)-LN(x+y)=LN[(x+y)/(x+y)]=LN(1)=0)
The relation you have shown is not a function.
In order to be a function, a relation's domain must be continuous in that no x-value is not repeated in any of the points. Since the first two points of the relation are (5,1) and (5,3), you can see that they have the same x-value, meaning that this is not a function.
One quick way you could test this is to quickly sketch a graph and use the vertical line test to see if the relation in question is a function. If it cross the vertical line once in all places, it is a function - if it crosses the vertical line more than once in any place, it is not a function.
Can you put a picture so we can see what it look like
Answer:
hi lol I need to type 20 characters
