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Neko [114]
3 years ago
15

Solve for w. 7w=-14 please help me with this one plz

Mathematics
2 answers:
kolezko [41]3 years ago
5 0

Answer: w = -2

Step-by-step explanation:

7w = -14

Divide both sides by 7

w = -2

That was brief but hope it helps!

Serga [27]3 years ago
4 0

Answer:

W = -2

Step-by-step explanation:

7W÷7      -14÷7

W= -2

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7 0
3 years ago
Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it. lim x→1 3x x − 1
Reika [66]

Answer:

<h2>3/2</h2>

Step-by-step explanation:

Given the limit of a function expressed as \lim_{x \to 1} (\dfrac{3x}{x-1} - \dfrac{3}{lnx}), we are to evaluate it. To evaluate it, we will simply substitute x = 1 into the function since the variable x tends to 1.

\lim_{x \to 1} (\dfrac{3x}{x-1} - \dfrac{3}{lnx})\\\\= (\dfrac{3(1)}{1-1} - \dfrac{3}{ln1})\\\\= \dfrac{3}{0} - \dfrac{3}{0}\\\\= \infty - \infty (ind)

Since we got an indeterminate function, we will find the LCM of the function and solve again.

= \lim_{x \to 1} (\dfrac{3x}{x-1} - \dfrac{3}{lnx})\\\\= \lim_{x \to 1} \dfrac{3xlnx-3(x-1)}{(x-1)lnx}\\\\\\= \dfrac{3(1)ln(1)-3(1-1)}{(1-1)ln1}\\\\= \frac{3(0)-3(0)}{0(0)} \\\\= \frac{0}{0} (ind)

Applying L'hospital rule;

\frac{x}{y} = \lim_{x \to 1} \dfrac{d/dx(3xlnx-3(x-1))}{d/dx((x-1)lnx)}\\\\=  \lim_{x \to 1} \dfrac{3x(\frac{1}{x})+ 3lnx-3)}{(x-1)\frac{1}{x} +lnx}\\\\= \lim_{x \to 1} \dfrac{3 + 3lnx-3}{(x-1)\frac{1}{x} +lnx}\\\\= \frac{3ln1}{(1-1)\frac{1}{1} +ln1}\\\\= \frac{0}{0} (ind)

Applying L'hospital rule again;

= \lim_{x \to 1} \dfrac{\frac{d}{dx} (3lnx)}{\frac{d}{dx} ((x-1)\frac{1}{x} +lnx)}\\\\=  \lim_{x \to 1} \dfrac{\frac{3}{x} }{(x-1)\frac{-1}{x^2} + \frac{1}{x} +\frac{1}{x} }\\\\= \dfrac{\frac{3}{1} }{(1-1)\frac{-1}{1^2} + \frac{1}{1} +\frac{1}{1} }\\\\= \frac{3}{0(-1)+2}\\ \\= \frac{3}{2-0}\\ \\= 3/2

<em>Hence the limit of the function is 3/2.</em>

7 0
3 years ago
Worth brainlist!!!!!!!!!!!!!
Ilya [14]

Answer: The answer to part a is 5 not 8

The MAD in part b is 10

since the median is 5

you go through all the 8 selections subtracting them by 5

-1, -2, -1, 0, 1, 1, 3,-1

since the numbers cant be negative you make them all positve which equals 10

8 0
3 years ago
The highway department has to plant 4245 trees along a 58 mile highway. The trees must be planted an equal distance apart. How m
bixtya [17]

Answer:

73 trees can be planted on equal distance and 11 trees would be left over.

Step-by-step explanation:

Given:

Number of trees to be planted = 4245

Number of miles of highway = 58

We need to find Number of trees can be planted in equal distance and number of trees to be left over.

Solution:

Now we can say that;

Number of trees can be planted in equal distance can be calculated by dividing Number of trees to be planted by Number of miles of highway.

framing in equation form we get;

Number of trees can be planted in equal distance = \frac{4245}{58} = 73.189

73\times58 = 4234

5245-4234 = 11

So we can say that.

73 trees can be planted on equal distance and 11 trees would be left over.

7 0
3 years ago
Pls answer show your work
____ [38]

Answer:

32

Step-by-step explanation:

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8 0
3 years ago
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