Determine whether quadrilateral EFGH is similar to quadrilateral QRST. If so, give the similarity statement. (ASAP PLS HELP!!)
2 answers:
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Answer:
2395 cm²
Step-by-step explanation:
You need to find the area of each side of the prism.
the first side is 3.5x24 which equals 840. there are two of those sides since it's a prism, so multiply by 2. 840x2=1680.
the second side is 13x3.5 which is 45.5. multiply that by 2 for the other side, 45.5x2=91.
repeat for the third side: 24x13=312. 312x2=624.
add all of the sides up to get total surface area. 624+91+1680=2395. :)
<h3>Answer: choice A) 55.3%</h3>
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Explanation:
Use a Z table found in the back of your book to find that
P(Z < -0.41) = 0.3409
P(Z < 1.25) = 0.8944
So,
P(-0.41 < Z < 1.25) = P(Z < 1.25) - P(Z < -0.41)
P(-0.41 < Z < 1.25) = 0.8944 - 0.3409
P(-0.41 < Z < 1.25) = 0.5535
Now convert this to a percentage by multiplying by 100, which is the same as moving the decimal point over 2 places
0.5535 ---> 55.35%
Round this to the nearest tenth of a percent. You could argue that 55.35% rounds to either 55.3% or 55.4% since that last digit is a 5. I'm going with 55.3% since 55.4% isn't listed as an answer choice. The table I used only lists approximate values, so there is likely some rounding error somewhere. When I used my TI83 (see image below) I got roughly 0.5534 which is fairly close to 0.5535. If you want to use your TI83 or TI84 calculator, then the normalcdf function can be found by pressing the yellow "2ND" button (top left corner) and then pressing the VARS key (3rd row from the top, just to the left of the CLEAR key).
Answer:
0.20 and 0.36
Step-by-step explanation:
y(t) = 2 sin (4π t) + 5 cos (4π t)
We wish to convert this to:
y = A sin(ωt + φ)
We know that ω = 4π. We also know the following:
5 = A sin φ
2 = A cos φ
Divide the first equation by the second equation:
5/2 = tan φ
φ = tan⁻¹(5/2)
Now, square the two equations and add them together.
5² + 2² = (A sin φ)² + (A cos φ)²
29 = A²
A = √29
The equation of the wave is therefore:
y = √29 sin(4π t + tan⁻¹(5/2))
The maximum negative position is -√29. And half of that is -½√29.
-½√29 = √29 sin(4π t + tan⁻¹(5/2))
-½ = sin(4π t + tan⁻¹(5/2))
7π/6 + 2kπ or 11π/6 + 2kπ = 4π t + tan⁻¹(5/2)
7 + 12k or 11 + 12k = 24t + 6 tan⁻¹(5/2) / π
t = (7 + 12k − 6 tan⁻¹(5/2) / π) / 24 or (11 + 12k − 6 tan⁻¹(5/2) / π) / 24
Trying different integer values of k, we find there are two possible values for t between 0 and 0.5, both when k = 0.
t = (7 − 6 tan⁻¹(5/2) / π) / 24 or (11 − 6 tan⁻¹(5/2) / π) / 24
t ≈ 0.20 or 0.36
