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Andre45 [30]
3 years ago
7

Lauren says that -3.5 is greater than -3 1/3. Do you agree? Explain.

Mathematics
1 answer:
kirza4 [7]3 years ago
3 0

Answer:

-3\frac{1}{2}

Step-by-step explanation:

-3.5 means -(3 + \frac{1}{2})

In other words, -3.5 = -3\frac{1}{2}

When we draw two numbers -3\frac{1}{3} and -3\frac{1}{2} on a number line, -3\frac{1}{2} comes first from left to right.

We know that all the numbers on a number line from left to right are in increasing order.

Therefore, -3\frac{1}{2} is smaller than -3\frac{1}{3}.

-3\frac{1}{2}

Lauren is not correct.

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The total amount repaid will be
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4 0
3 years ago
Cally made a rectangular sandbox. It is 8 feet long and 10 feet
Mnenie [13.5K]

Answer:

160 pounds of sand.

Step-by-step explanation:

7 0
3 years ago
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A cylinder has a circular base with a diameter of 12 ft the height of the cylinder is 4 feet what is the volume of the cylinder
Murrr4er [49]

Answer:

452\ ft^{3}

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

V=\pi r^{2} h

we have

r=12/2=6\ ft ----> the radius is half the diameter

h=4\ ft

substitute the values

V=(3.14)(6^{2})(4)=452\ ft^{3}

5 0
4 years ago
A table is shaped like a regular hexagon. The length of one side is (7x + 4) in. and the length of another side is (8x − 1) in.
kirza4 [7]

Answer:

39 in.

Step-by-step explanation:

As  it's a regular hexagon all sides are congruent.

Therefore

7x + 4 = 8x - 1

4 + 1 = 8x - 7x

x = 5.

So the required length is 7(5) + 4 = 39 in.

8 0
3 years ago
[Geometry Basics] I'm just checking if this is correct:
Leno4ka [110]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ x &,& y~) 
%  (c,d)
&&(~ -9 &,& -1~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left( \cfrac{-9+x}{2}~~,~~\cfrac{-1+y}{2} \right)=\stackrel{midpoint}{(8,14)}\implies 
\begin{cases}
\cfrac{-9+x}{2}=8\\\\
-9+x=16\\
\boxed{x=25}\\
-------\\
\cfrac{-1+y}{2} =14\\\\
-1+y=28\\
\boxed{y=29}
\end{cases}

\bf -------------------------------\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ x &,& y~) 
%  (c,d)
&&(~10 &,& 12~)
\end{array}\qquad
\\\\\\
\left( \cfrac{10+x}{2}~~,~~\cfrac{12+y}{2} \right)=\stackrel{midpoint}{(6,9)}\implies 
\begin{cases}
\cfrac{10+x}{2}=6\\\\
10+x=12\\
\boxed{x=2}\\
-------\\
\cfrac{12+y}{2} =9\\\\
12+y=18\\
\boxed{y=6}
\end{cases}
3 0
3 years ago
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