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1 answer:
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Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.
Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
Answer:
x = 2
Step-by-step explanation:
Given
See attachment
Required
What is the value of x?
The vertical axis represents f(x) while the horizontal represents x.
From the attachment:
f(x) = 2 when x = 2
The circled point on attachment 2 represents the required point
<em>Assume that each box is 1 unit.</em>
