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3 years ago

Find the slope and the y-intercept of the graph of the linear equation y=5/4x-7. The slope is ?, and the y-intercept is ?.

Mathematics

2 answers:

Tanya [424]3 years ago

7 0

Answer:

5/4 slope

-7 y intercept.

Step-by-step explanation:

The slope is the number in front of the x. The number in front of the x is 5/4. The slope is 5/4

1. The y intercept is whatever is behind the x or 0 if there is no number following the x.

2. The y intercept is also characterized by being on the same side of the equation as the x.

3. Finally it has no x in it.

In this case the y intercept is -7

Examples

y + 2 = x 2 is not the y intercept. subtract 2 from both sides. y = x - 2. Therefore -2 is the y intercept.

2y = 4x + 6 4 is not the slope. You have to divide by y = 2x+3. So 2 is the slope and 0,3 is the y intercept.

babunello [35]3 years ago

3 0

Answer:

Not Linear.

Step-by-step explanation:

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6. If F(x) = -6(2x2 + 5x) - 9, what is the value of F(-4)?

Soloha48 [4]

Answer:

-81

Step-by-step explanation:

-6(2x² + 5x) - 9

substitute -4 for 'x'

-6[2(-4)² + 5(-4)] - 9

-6[2(16) + (-20) - 9]

-6(32 - 20) - 9

-6(12) - 9

-72 - 9 = -81

5 0

3 years ago

SampleVarianceandStandardError: You encounter a deck of Martian playing cards.There are 87 cards in the deck. You cannot read Ma

docker41 [41]

Answer:

(a) The standard error of estimate of the fraction of blue cards in the deck is 0.145.

(b) The sample size required is 84.

Step-by-step explanation:

The proportion of blue cards is, p = 0.30.

The number of times the cards were shuffled is, n = 10.

(a)

The standard error for sample proportion is given by:

$SE_{p}=\sqrt{\frac{p(1-p)}{n}}$

Compute the value of standard error as follows:

$SE_{p}=\sqrt{\frac{p(1-p)}{n}}\\=\sqrt{\frac{0.30\times (1-0.30)}{10}}\\=\sqrt{0.021}\\=0.145$

Thus, the standard error of estimate of the fraction of blue cards in the deck is 0.145.

(b)

Now we need to reduce the standard error.

The standard error is inversely proportional to the sample size.

If the sample size is increased then the standard error will be decreased.

So we need to use a larger sample size.

Compute the value of n for standard error 0.05 and p = 0.30 as follows:

$SE_{p}=\sqrt{\frac{p(1-p)}{n}}\\0.05=\sqrt{\frac{0.30(1-0.30)}{n}}\\0.05^{2}=\frac{0.21}{n}\\n=84$

Thus, the sample size required is 84.

4 0

4 years ago

The half-life of Radium-226 is 1590 years. If a sample contains 500 mg, how many mg will remain after 2000 years? Preview mg Giv

d1i1m1o1n [39]

Answer:

$a_{n}$ =209.09 mg

Step-by-step explanation:

given: material= radium

half life= 1590 years

initial mass $a_{0}$ =500mg

we know that to calculate the amount left we use

$a_{n}$ = $a_{0}$ $\left ( 0.5\right )^{n}$

$n=\frac{2000}{1590} = 1.2578$

therefore

$a_{n}$ = $500\times0.5^{1.2578}$

$a_{n}$ =209.09058407921 mg

$a_{n}$ =209.09 mg amount left after 2000 years

4 0

4 years ago

Which of the following point is located on the line represented by the equation y + 4 = -5 (x - 3)?. .

horsena [70]

If we plug in: x = 3, y= - 4;
- 4 + 4 = - 5 · ( 3 - 3 )
0 = 0 ( correct )
Answer: C ) ( 3, - 4 )

3 0

3 years ago

Tucker and Jeremy went scuba diving in the ocean together. Tucker dove to a depth of -115 feet, while

makkiz [27]

Answer= Tucker
-115 feet into the ocean is deeper than -109 feet

8 0

3 years ago