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Schach [20]
3 years ago
5

Please help me with #2

Mathematics
1 answer:
zaharov [31]3 years ago
6 0
Let the nomber of 2 pointers be x and that of 3 pointers be y, then
2x + 3y = 30 . . . (1)
x = y + 5 . . . (2)

Putting (2) into (1), gives 2(y + 5) + 3y = 30
2y + 10 + 3y = 30
5y = 30 - 10 = 20
y = 20/5 = 4
x = 4 + 5 = 9
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TIMED TEST PLEASE HELP
xxMikexx [17]
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=18,749.28
Interest paid
18,749.28−16,000
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Larry will save of taking 6% loan
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2) credit card 1
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277.09×12
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3,325.08−3,000
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Hope it helps!
6 0
3 years ago
Read 2 more answers
The following triangles are similar. Find x.
AlladinOne [14]

Let's use the line on the right side. In the smaller triangle, the length is 4. The same side on the bigger triangle is 12. The ratio of the smaller triangle to the bigger triangle is:

\frac{4}{12} \rightarrow 4:12

12 \div 4 = 3

To find a side length for the bigger triangle, all you need to do is multiply by 3. The same side on the smaller triangle is 5. Multiply by 3

5 \times 3 = 15

That means x = 15

8 0
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Help Please! I will mark you as brainlyest!!!
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