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ankoles [38]
3 years ago
14

Please help i only have a few minutes left

Mathematics
1 answer:
Leni [432]3 years ago
6 0

Answer:

Negative effects of the Mongol Empire's expansion into Western europe, East Asia, include the wiping out of people that resisted given the violent nature of their invasions.

Positive effects include a century of peace those under under Mongol rule. This stability allowed for the reopening of the Silk Road trading routes between China and Europe, increasing cultural exchange and wealth all along the trade paths including Western Africa, East Asia and Europe.

Step-by-step explanation:

You might be interested in
5.) 3x^2 - 13x + 4 = 0
Anna71 [15]

Answer:

Answer:

x= 1/3 or x=4

Step-by-step explanation:

Let's solve your equation step-by-step.

3x2−13x+4=0

Step 1: Factor left side of equation.

(3x−1)(x−4)=0

Step 2: Set factors equal to 0.

3x−1=0 or x−4=0

x= 1/3or x=4

plz give brainlyest

7 0
3 years ago
if the measure of <BEC is (2x+3)° and x=30, which expression could represent the measure of <AED?​
Maurinko [17]

Answer:

The answer is 3x-27

Step-by-step explanation:

If the angles are vertical from each other it means they are congruent. 2x+30 is 63, you plug in the x, 2(30)+30. You do that to the second one and also get 63, 3(30)-27. Therefore 3x-21 is the answer.

8 0
3 years ago
Need help..thanks......
Vinvika [58]

Answer: D) Flat area with a large number of plants

The roots of the plants hold in the soil, which prevents/reduces erosion.

The steeper slope means gravity pulls down the soil material faster, since there is less ground in the way to hold it up, so to speak. So flatter areas are less prone to erosion compared to steeper areas.

So that's why overall, flatter areas with lots of plants would have the least erosion.

7 0
3 years ago
Cual es el resultado de 12/6?
oksano4ka [1.4K]

Answer:

Resultado es dos (2)

3 0
2 years ago
Read 2 more answers
Write as a single logarithm 3-1/2(log6+log3-3log2)
faust18 [17]
3-\dfrac{1}{2}\left(\log6+\log3-3\log2\right)=\\
\log10^3-\dfrac{1}{2}\left(\log\left(6\cdot3\right)-\log2^3\right)=\\
\log1000-\dfrac{1}{2}\left(\log18-\log8\right)=\\
\log1000-\dfrac{1}{2}\left(\log\dfrac{18}{8}\right)=\\
\log1000-\dfrac{1}{2}\left(\log\dfrac{9}{4}\right)=\\
\log1000-\log\left(\dfrac{9}{4}\right)^{\dfrac{1}{2}}=\\
\log1000-\log\sqrt{\dfrac{9}{4}}=\\
\log1000-\log\dfrac{3}{2}=\\
\log\dfrac{1000}{\frac{3}{2}}=\\
\log\left(1000\cdot\dfrac{2}{3}\right)=\\
\log\dfrac{2000}{3}
6 0
3 years ago
Read 2 more answers
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