All categories

3 years ago

A (0,0) B(-6,0) C (-6, 3) (x,y) - (x + 6, y + 3)

Mathematics

1 answer:

juin [17]3 years ago

3 0

Answer:

plz send full question

Step-by-step explanation:

according to your book

You might be interested in

A tv costs £800. Work out the price after a 3% discount.

Blababa [14]

3% = 800/ 100 = 8, 8x3= 24

800-24 = 776

£776

5 0

3 years ago

Read 2 more answers

In the line 3y=4x-1 and 9y=x+3 are parallel to each other the value of q is

jonny [76]

Do you mean the value of y? there is no q in these equations.

5 0

3 years ago

Read 2 more answers

Based on the graph, which inequality is correct for a number that is to the right of -4

Anon25 [30]

2 > -4

2 is greater than -4

3 0

4 years ago

Translate the sentence into an equation. Six more than the quotient of a number 5 and 9 equals . Use the variable y for the unkn

sashaice [31]

the answer is 6+5y=9

7 0

3 years ago

A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6

katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is $49\ ft$

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

$h(t)=-16t^{2} +63t+4$

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

$h(3)=-16(3)^{2} +63(3)+4=49\ ft$

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

Convert the function into a vertex form

$h(t)=-16t^{2} +63t+4$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$h(t)-4=-16t^{2} +63t$

Factor the leading coefficient

$h(t)-4=-16(t^{2} -(63/16)t)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})$

$h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})$

Rewrite as perfect squares

$h(t)-(67,600/1,024)=-16(t-(63/32))^{2}$

$h(t)=-16(t-(63/32))^{2}+(67,600/1,024)$

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

$h(t)=-16t^{2} +63t+4$

For h(t)=0

$0=-16t^{2} +63t+4$

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0

3 years ago