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3 years ago

What is the area of this composite figure 48.56cm2 49.12cm2 74.24cm2 36.56cm2

Mathematics

1 answer:

Vlada [557]3 years ago

6 0

Answer:

D. 36.56 cm²

Step-by-step explanation:

The composite figure is composed of a rectangle and two semicircles.

The two semicircles makes 1 full circle.

Thus:

Area of the composite figure = area of rectangle + area of circle

= L*W + πr²

L = 6 cm

W = 4 cm

r = ½(4) = 2 cm

Area = 6*4 + π*2²

Area = 24 + 12.56

Area = 36.56 cm²

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Hey there,
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Is the following relation a function? 1) Yes 2) No

lesantik [10]

To figure out if the given relation is a function, we first need to know what a function is:

Function: A relation which relates the element x of set X with a single element of set Y

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3 years ago

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PLEASE HELP

bonufazy [111]

Answer:

The probability that you will get two of the same colored gumballs WITHOUT reposition is 5/15,972 or 0.0003%, and the probability that you will get two of the same colored gumballs WITH reposition is 1/1,296 or 0.0008%

Step-by-step explanation:

Let's recall that the formula of the probability is:

Probability = Number of favorable outcomes/Total number of favorable outcomes

Total number of favorable events = 4 + 6 + 2 = 12

Reposition means that we take the gumball and put it back in the machine.

1. Therefore, the probability of getting two green gumballs without reposition is:

Probability of the 1st gumball to be green = 4/12

Probability of the 2nd gumball to be green = 3/11

Probability of getting two green gumballs without reposition = 4/12 * 3/11 = 12/132 = 3/33 = 1/11

The probability of getting two green gumballs with reposition is:

Probability of the 1st gumball to be green = 4/12

Probability of the 2nd gumball to be green = 4/12

Probability of getting two green gumballs with reposition = 4/12 * 4/12 = 16/144 = 1/9

2. Therefore, the probability of getting two red gumballs without reposition is:

Probability of the 1st gumball to be red = 6/12

Probability of the 2nd gumball to be red = 5/11

Probability of getting two red gumballs without reposition = 6/12 * 5/11 = 30/132 = 5/22

The probability of getting two red gumballs with reposition is:

Probability of the 1st gumball to be red = 6/12

Probability of the 2nd gumball to be red = 6/12

Probability of getting two red gumballs with reposition = 6/12 * 6/12 = 36/144 = 1/4

3. Therefore, the probability of getting two yellow gumballs without reposition is:

Probability of the 1st gumball to be yellow = 2/12

Probability of the 2nd gumball to be yellow = 1/11

Probability of getting two yellow gumballs without reposition = 2/12 * 1/11 = 2/132 = 1/66

The probability of getting two yellow gumballs with reposition is:

Probability of the 1st gumball to be yellow = 2/12

Probability of the 2nd gumball to be yellow = 2/12

Probability of getting two red gumballs with reposition = 2/12 * 2/12 = 4/144 = 1/36

Finally, the probability that you will get two of the same colored gumballs WITHOUT reposition is:

1/11 * 5/22 * 1/66 = 5/15.972 or 0.0003%

and the probability that you will get two of the same colored gumballs WITH reposition is:

1/9 * 1/4 * 1/36 = 1/1,296 or 0.0008%

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3 years ago