Step-by-step explanation:
1. we have to write the system specifications as:
A(x,y) give us the meaning that the consule x can be accessed when y is in a faulty condition
∀y∃A(x,y)
2. B(x,y) shows that users email has sent a message, y. Which is in the archive. C(x) shows the email address of user x is retrievable
∀x∃y[B(x,y)→c(x)]
3. D(x,y) shows that x can detect breach y'' and we have E(z) that tells us there is a compromise of z
∀y∃xD(x,y)↔ ∃zE(z)
4. F(x,y,z)
Y and z are distinct point ends which x connects
We have,
∀y∀z∃x∃a[x ≠a →F(x,y,z)^F(a,y,z)
5. G(x,y)
X knowst the password of y' and H(x) means that we have x to be a system administrator
∀x[H(x)→∀yG(x,y)] ∃x[H(x)^∀yG(x,y)]
Answer: B
Step-by-step explanation:
2(—2) + 10 = 6.
2(0) + 6 = 6.
2(2) + 2 = 6.
2(4) + (—2) = 6
We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d
we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor
p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)
therefor
p=d(x+4) and
x^2-5x+6=d(x-2)
we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub
p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
Answer:
10 sqrt(269) = c
164.0121947 = c
Step-by-step explanation:
The diagonal is the hypotenuse of the right triangle
The length and width are the legs of the right triangle
We can use the Pythagorean theorem
a^2 + b^2 =c^2
100^2 + 130^2 = c^2
10000+16900 = c^2
26900 = c^2
Take the square root of each side
sqrt(26900) = sqrt(c^2)
sqrt( 269) sqrt(100) = c
10 sqrt(269) = c
164.0121947 = c