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mihalych1998 [28]
3 years ago
15

#4 Find the value of x. Round your answer to the nearest tenth.

Mathematics
1 answer:
Klio2033 [76]3 years ago
7 0

Answer:

<h2>x (rounded) = 19.1</h2>

Step-by-step explanation:

Since The figure shows a right triangle then

cos(43)=\frac{14}{x} \\\\Then\\x=\frac{14}{cos(43)} \\\\Then\\x=19.14258445538

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What is the answer to -5(-3w-8)=21 for w
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Answer:

w = -1.266

Step-by-step explanation:

distribute the 5 by everything in the parenthesis and then bring everyhting down then you should have a regular equation to work w

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5.44nL to mL convert
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5.44nl \times \frac{1ml}{1000000nl} = 0.00000544ml
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The shape of the distribution of the time required to get an oil change at a 20 minute oil change facility. However, records ind
Katyanochek1 [597]

Answer:

For a mean oil change time of 20.51 minutes there would be a​ 10% chance of being at or​ below

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 21.3, \sigma = 3.9, n = 40, s = \frac{3.9}{\sqrt{40}} = 0.6166

Treating this as a random​ sample, at what mean​ oil-change time would there be a​ 10% chance of being at or​ below?

This is the 10th percentile, which is X when Z has a pvalue of 0.1. So it is X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-1.28 = \frac{X - 21.3}{0.6166}

X - 21.3 = -1.28*0.6166

X = 20.51

For a mean oil change time of 20.51 minutes there would be a​ 10% chance of being at or​ below

6 0
3 years ago
The amount of protein that an individual must consume is different for every person. There are solid theoretical ideas that sugg
amid [387]

Answer:

The proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is 0.239, that is, 239 persons for every 1000, or simply 23.9% of them.

\\ 0.239 =\frac{239}{1000}\;or\;23.9\%

Step-by-step explanation:

From the question, we have the following information:

  • The distribution for protein requirement is <em>normally distributed</em>.
  • The population mean for protein requirement for adults is \\ \mu= 0.65 gP*kg^{-1}*d^{-1}
  • The population standard deviation is \\ \sigma =0.07 gP*kg^{-1}*d^{-1}

We have here that protein requirements in adults is normally distributed with defined parameters. The question is about <em>the proportion</em> <em>of the population</em> that has a requirement less than \\ x = 0.60 gP*kg^{-1}*d^{-1}.

For answering this, we need to calculate a <em>z-score</em> to obtain the probability of the value <em>x </em>in this distribution using a <em>standard normal table</em> available on the Internet or on any statistics book.

<h3>z-score</h3>

A z-score is expressed as

\\ z = \frac{x - \mu}{\sigma}

For the given parameters, we have:

\\ z = \frac{0.60 - 0.65}{0.07}

\\ z = \frac{0.60 - 0.65}{0.07}

\\ z = -0.7142857

<h3>Determining the probability</h3>

With this value for <em>z</em> at hand, we need to consult a standard normal table to determine what the probability of this value is.

The value for z = -0.7142857 is telling us that the requirement for protein is below the population mean (negative sign indicates this). However, most standard normal tables give a probability that a statistic is less than z and for values greater than the mean (in other words, positive values). To overcome this, we need to take the complement of the probability given for z-score z = 0.7142857, that is, subtract from 1 this probability, which is possible because the normal distribution is <em>symmetrical</em>.

Tables have values for <em>z</em> with two decimal places, then, for z = 0.7142857, we need to rewrite it as z = 0.71. For this value, the <em>standard normal table</em> gives a value of P(z<0.71) = 0.76115.

Therefore, the cumulative probability for values less than x = 0.60 which corresponds to a z-score = -0.7142857 is approximately:

\\ P(x

\\ P(x (rounding to three decimal places)

That is, the proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is

\\ 0.239 =\frac{239}{1000}\;or\;23.9\%

See the graph below. The shaded area is the region that represents the proportion asked in the question.

5 0
3 years ago
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