Answer:
For example, if you wish to find the average grade on a test for your class but one student fell asleep and scored a 0, the mean would show a much lower average because of one low grade, while the median would show how the middle group of students scored.
Step-by-step explanation:
Answer:
a) 131/450
b) 1233/1276
Step-by-step explanation:
P(bad) = P(1st batch)*P(bad 1st batch ) + P(2nd batch )*P(bad 2nd batch) + P(3rd batch )*P(bad 3rd batch)
p(bad) =(60/360)*(1/3) + (120/360)*(1/4 ) + (180/360)*(1/5)
= 43/180
And that of P(good )
= 1 - 43/180
= 137/180
a)
P(defective) = P(bad)*P(defective /bad) + P(good)*P(defective /good)
= (43/180)*(9/10) + (137/180)*(1/10)
= 131/450
b)
P(Bc I Dc ) = P(good)*P(not defective |good) / P(not defective)
= (137/180)*(1 - 1/10) / (1 - 131/450)
= 1233/1276
1.754
Because without the decimal 54 is more than 48 (a little trick I used)
I think the correct answer is C
