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3 years ago

10

M is between N and O . MO = 15, and MN = 76. Find NO

1 answer:

I am Lyosha [343]3 years ago

8 0

Answer:

<h2> 91 </h2>

Step-by-step explanation:

N___________________<u>M</u>_______O

76 15

NO = MN + MO = 76 + 15 = 91

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Tasha has 8 more fish than Oscar, who had twice as many fish as Cecilia. If altogether they have 148 fish, how many fish do each

yKpoI14uk [10]

Equation: x+2x+(2x+8)=148

Solve for x: 5x+8=148
5x=140
x=28

Plug back into original equation to find the other two amounts:
28+2(28)+[2(28)+8]=148
Cecilia = 28, Oscar = 56, Tasha = 64

Check: 28+56+64= 148
148=148
The solutions work

Cecilia has 28 fish, Oscar has 56 fish, and Tasha has 64 fish

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2 years ago

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Viktor [21]

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3 years ago

Find f(-5) if f(n) = n3 + 3n2

KATRIN_1 [288]

The answer is -50 because -5 squared is 25 and that times 3 is 75 -5 cubed is -150 and -150 + 75 is 50

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3 years ago

A factory received a shipment of 11 hammers, and the vendor who sold the items knows there are 2 hammers in the shipment that ar

zhenek [66]

Question:

If a sample of 2 hammer is selected

(a) find the probability that all in the sample are defective.

(b) find the probability that none in the sample are defective.

Answer:

a $Pr = \frac{2}{110}$

b $Pr = \frac{72}{110}$

Step-by-step explanation:

Given

$n = 11$ --- hammers

$r = 2$ --- selection

This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities

Solving (a): Probability that both selection are defective.

For two selections, the probability that all are defective is:

$Pr = P(D) * P(D)$

$Pr = \frac{2}{11} * \frac{2-1}{11-1}$

$Pr = \frac{2}{11} * \frac{1}{10}$

$Pr = \frac{2}{110}$

Solving (b): Probability that none are defective.

The probability that a selection is not defective is:

$P(D') = \frac{9}{11}$

For two selections, the probability that all are not defective is:

$Pr = P(D') * P(D')$

$Pr = \frac{9}{11} * \frac{9-1}{11-1}$

$Pr = \frac{9}{11} * \frac{8}{10}$

$Pr = \frac{72}{110}$

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2 years ago

Greg ran 3 times as far as jed.rj ran 0.1times as far as Greg. If jed ran25 yards, how far did Greg and rj run

azamat

Greg's distance is 3 times than Jed. so, 25 yards * 3 = 75 yards. And RJ ran only 0.1 times than Greg (75 yards). So, it should be 7.5 yards

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3 years ago