IQR = 40
1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.
We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.
40, 45, 50, 60, 60, 75, 90, 90, 120
Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;
IQR = 90 - 50 = 40
Answer:
y =7
x =14
Step-by-step explanation:
Since this is a right triangle we can use trig functions
tan 30 = opp /adj
tan 30 = y/ 7 sqrt(3)
7 sqrt(3) tan 30 = y
7 sqrt(3) * 1/ sqrt(3) =t
7 =y
sin 30 = opp/ hyp
sin 30 = 7/x
x sin 30 =7
x = 7/ sin 30
x = 7 / 1/2
x = 14
Answer:
3m - 8
Step-by-step explanation:
Step by Step:
Equation= 6m³ - 16m² + 15m - 40/ 2m² + 5
Factor out 2m² from 6m³ - 16m²:
Factor out 5 from expression:
2m²(3m - 8) + 5(3m - 8)/2m² + 5
Factor out 3m - 8:
(3m - 8)(2m² + 5)/2m² + 5
Rude the fraction with 2m² + 5:
3m - 8 is the answer
I hope this helped!
Answer: $20.60
Step-by-step explanation:
20 × 3% = .60
20 + .60 = 20.60
