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3 years ago

What program is considered the industry standard for digital graphics and image editing?

Computers and Technology

2 answers:

Nataly_w [17]3 years ago

8 0

Photoshop is the program that is considered the industry standard for digital graphics and image editing.

Adobe Photoshop is the industry-standard image editor that is used to create, design and edit raster images as well as to add effects, shadows and textures to existing designs.

denpristay [2]3 years ago

7 0

I believe photoshop, or illustrator

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Let cell E2 = 100, what is the result of this formula? =NOT(E2<100) *

lukranit [14]

Answer:

True

Explanation:

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3 years ago

What is a partition gap, and how might it be used to hide data?â?

o-na [289]

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3 years ago

Read 2 more answers

Write a Twitter class that sets the Twitter user first (who is to be followed) and lets the client add up to 5 followers, which

SSSSS [86.1K]

Answer:

C++ code explained below with its sample outputs

Explanation:

Twitter.h

========

#ifndef Twitter_h

#define Twitter_h

#include <iostream>

using std::string;

using std::cout;

using std::endl;

template <typename T>

class Twitter

{

private:

string name;

T followers[5];

int numFollowers;

public:

Twitter(string n);

bool AddFollower(T follower);

bool RemoveFollower(T follower);

void PrintFollowers();

};

template <typename T>

Twitter<T>::Twitter(string n)

{

name = n;

numFollowers = 0;

}

template <typename T>

bool Twitter<T>::AddFollower(T follower)

{

if(numFollowers < 5)

{

followers[numFollowers] = follower;

numFollowers++;

return true;

}

else

return false;

}

template <typename T>

bool Twitter<T>::RemoveFollower(T follower)

{

int index;

bool found = false;

for(index = 0; index < numFollowers; index++)

{

if(followers[index] == follower)

{

found = true;

break;

}

if(found)

{

//shift all other followers after the one to be removed to one position left

for(++index; index < numFollowers; ++index)

{

followers[index-1] = followers[index];

}

numFollowers--;

return true;

}

else

return false;

}

template <typename T>

void Twitter<T>::PrintFollowers()

{

cout << "Followers for " << name << endl;

for(int i = 0; i < numFollowers; i++)

cout << followers[i] << endl;

cout << "------" << endl << endl;

}

#endif /* Twitter_h */

main.cpp

=========

#include "Twitter.h"

#include <iostream>

using namespace std;

struct Profile {

string userName;

int age;

string state;

};

ostream& operator << (ostream & output, Profile p) {

output << p.userName;

return output;

}

bool operator == (const Profile &p1, const Profile p2)

{

return p1.userName == p2.userName;

}

int main()

{

Twitter<string> t1("John");

Twitter<Profile> t2("Bob");

cout << "Adding followers to John" << endl;

t1.AddFollower("Bill");

t1.AddFollower("Jack");

t1.PrintFollowers();

Profile p1 = {"Alice", 20, "Alaska"};

Profile p2 = {"Janet", 22, "California"};

Profile p3 = {"Jim", 20, "Texas"};

cout << "Adding follower profiles to Bob" << endl;

t2.AddFollower(p1);

t2.AddFollower(p2);

t2.AddFollower(p3);

t2.PrintFollowers();

cout << "Removing Bill from John" << endl;

t1.RemoveFollower("Bill");

cout << "Removing Janet's profile from Bob" << endl << endl;

t2.RemoveFollower(p2);

t1.PrintFollowers();

t2.PrintFollowers();

}

output

-======

Adding followers to John

Followers for John

Bill

Jack

------

Adding follower profiles to Bob

Followers for Bob

Alice

Janet

Jim

------

Removing Bill from John

Removing Janet's profile from Bob

Followers for John

Jack

------

Followers for Bob

Alice

Jim

------

6 0

3 years ago

Describe the Sign in process of an Email account.

Inga [223]

User inputs email. User inputs password , if password and username match user allowed through.If not password or email address is incorrect notification is shown - and there also may be a limit on the amount of attempts you have to get it right.

8 0

3 years ago

Write a C++ program that searches for anagrams in a dictionary. An anagram is a word obtained by scrambling the letters of some

Semmy [17]

Answer:

d, avt, car, feet, more, pitch, rome, tac, teef,

Anagrams of b in dictionary

Anagrams of cat in dictionary

avt, cat, tac,

Anagrams of room in dictionary

more, rome,

Anagrams of hello in dictionary

Anagrams of in dictionary

Explanation:

// FindAnagrams.cpp : it is the starting point of application console.

#include <vector>

#include <hash_map>

#include <iostream>

#include <string>

#include <algorithm>

#include <map>

#include <set>

using namespace std;

using namespace stdext;

bool IsAnagrams(string& strA, string& strB)

{

list<char> listA(strA.begin(), strA.end());

list<char> listB(strB.begin(), strB.end());

listA.sort();

listB.sort();

return listA == listB;

// return equal(listA.begin(), listA.end(), listB.begin());

}

string SortChars(string str)

{

list<char> l(str.begin(), str.end());

l.sort();

return string(l.begin(), l.end());

}

set<string> FindAnagrams(list<string>& dict, string findStr)

{

map<string, set<string>> d;

typedef pair<string, set<string>> MyPair;

for(list<string>::const_iterator it = dict.begin(); it != dict.end(); ++it){

string str(SortChars(*it));

if(d.find(str) == d.end()){

set<string> s;

s.insert(*it);

d.insert(MyPair(str, s));

}

else{

d[str].insert(*it);

}

string sortedStr(SortChars(findStr));

return d[sortedStr];

}

int main(int argc, char* argv[])

{

list<string> dict;

dict.push_back("c");

dict.push_back("car");

dict.push_back("avt");

dict.push_back("taac");

dict.push_back("feet");

dict.push_back("teef");

dict.push_back("rom");

dict.push_back("more");

dict.push_back("pit");

dict.sort();

cout << "The dictionary: " << endl;

copy(dict.begin(), dict.end(), ostream_iterator<string>(cout, ", "));

cout << endl;

list<string> testCases;

testCases.push_back("d");

testCases.push_back("car");

testCases.push_back("rome");

testCases.push_back("hell");

testCases.push_back("");

for(list<string>::iterator it = testCases.begin(); it != testCases.end(); ++it)

{

cout << endl << "Anagrams of " << *it << " in dictionary" << endl;

set<string> output = FindAnagrams(dict, *it);

copy(output.begin(), output.end(), ostream_iterator<string>(cout, ", "));

cout << endl;

}

return 0;

}

8 0

3 years ago