Answer:
for(i = 0 ; i < NUM_VALS; ++i)
{
cout << courseGrades[i] << " ";
}
cout << endl;
for(i = NUM_VALS-1 ; i >=0 ; --i)
{
cout << courseGrades[i] << " ";
}
cout << endl;
Explanation:
The first loop initializes i with 0, because we have to print the elements in order in which the appear in the array. We print each element, adding a space (" ") character at its end. After the loop ends, we add a new line using endl.
The second loop will print the values in a reverse order, so we initialize it from NUM_VALS-1, (since NUM_VALS = 4, and array indices are 0,1,2,3). We execute the loop till i >= 0, and we print the space character and new line in a similar way we executed in loop1.
Answer:
Programmers can take advantage of abstraction to focus on specific tasks.
Explanation:
When we excel in some subjects, we can do abstraction in that subject. Abstraction means you understand by the term, and you do not need details of that term. Like you say some tasks will be done by a graphic designer as a project manager, and you do not need to understand at that point what he will be doing, and that is because you can write in a word or few what is going to be the outcome. And hence, the programmers can take advantage of abstraction to focus on specific tasks. And this is the correct option.
Answer:
Sandboxing.
Explanation:
SDLC or software development life cycle is a systematic approach to software development. It marks the birth and death of an application.
The application development starts from the research of the properties of the application to the design and development or implementation of the application.
After the implementation of the software, it is tested, comparing the design and the codes in the development process. The sandboxing testing process helps to isolate and test new lines of code added during the testing phase.
Answer:
layout, next page, continuous
Explanation:
just took it
Answer:
Aqueous carbon dioxide, CO2 (aq), reacts with water forming carbonic acid, H2CO3 (aq). Carbonic acid may loose protons to form bicarbonate, HCO3- , and carbonate, CO32-. In this case the proton is liberated to the water, decreasing pH. The complex chemical equilibria are described using two acid equilibrium equations.
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