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Simora [160]
3 years ago
6

Explain how grality and electric charge are different

Physics
1 answer:
stich3 [128]3 years ago
6 0
A difference between the two forces is the fact that gravitation only attracts, while electrical forces attract when the electrical charges are opposite and repel if the charges are similar. Thus, gravitation is considered a monopole force, while electrostatics is a dipole force. Please mark me as a brainiest!!!
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For an extended object, the weight force can be considered to act at which point?
JulsSmile [24]

Answer:

At the center of the object

At the end of the object farthest away from the ground

At the center of gravity of the object

At end of the object closest to the ground

Explanation:

5 0
3 years ago
Which would hold more water- a teaspoon (tsp) or a milliliter?
ki77a [65]
A tsp

1 milliliter equals 0.202. US teaspoons. boi did that help
4 0
3 years ago
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I WILL MARK BRAINIEST!!
Ivahew [28]
The answer is as the slope of the line
3 0
3 years ago
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J. Ram travels 50 m on a straight road in 30 s. Hari covers the same distance
ira [324]

Explanation:

Explanation:

In the given question, there are two conditions.

Ram traveled 50 m in 30 seconds in a straight road.

Hari covers the same distance in the road; that means 50 m in 45 seconds

The formula for work w=\frac{d}{t}w=td

Ram's work w=\frac{50}{30}=1.66666w=3050=1.66666

Hari's work w=\frac{50}{45}=1.111w=4550=1.111

Ram is slower than Hari and the velocity of Ram is slower than Hari.

Ram has done less work than Hari.

Hence, Hari has done more work and he has more power than Ram.

6 0
2 years ago
One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching this
Afina-wow [57]

Answer:27^{\circ}

Explanation:

Given

Initial velocity of both snowball is 29.3 m/s

first snowball launch angle=63^{\circ}

Considering motion of snowball to be projectile

range is given by

R=\frac{u^2\sin 2\theta }{g}

R=\frac{29.3^2\sin 126}{9.8}

R=70.87 m-----1

If second snowball is thrown at an angle of \phi

R=\frac{u^2\sin 2\phi }{g}

R=\frac{29.3^2\sin 2\phi }{9.8}------2

70.87=87.601\sin 2\phi

0.809=\sin \phi

2\phi can be 53.99^{\circ}

or 180-2\phi =53.99^{\circ}

Thus \phi =26.995 \approx 27^{\circ}

4 0
3 years ago
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