I think it would be WEIGHT and ROUGHNESS OF SURFACE.
Answer:
0.113097335529 Nm
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
a = Acceleration
I = Moment of inertia = 0.3 kgm²

Torque is given by

The magnitude of torque is 0.113097335529 Nm
A ) v = v o - a t
0 = 22 - a · t
a · t = 22
d = v o · t - a t²/2
0.04 = 22 t - 22 t / 2
0.04 = 11 t
t = 0.04 : 11 = 0.003636 s
a = 22 / t
a = 6050 m/s²
F = m · a = 0.09 kg · 6050 m/s²
F ( target→arrow) = - 544.5 N
b ) F ( arrow→target ) = 544.5 N
c ) If the speed was doubled: v = 44 m/s;
F = a m
a = 6050 m/s²
a · t = 44
t = 6050 : 0.04
t = 0.007272 s
d = 44 t - 44 t/2 = 22 t
d = 22 · 0.007272
d = 0.16 m = 16 cm
Answer:
a) horizontal range s=277671.77 m
b) time the shell is in motion 301.143 s
Explanation:
Is a parabolic movement so the velocity have two components:

°








