Answer:
When the volume of a gas in a container varies inversely with the pressure on the gas and a container of nitrogen has a volume of 29.5 litres with 2000 psi. So, if the tank has a 14.7 psi pressure, then the volume of the tank would be 4013.6 litres.
Step-by-step explanation:
- The volume of a gas in a container varies inversely with the pressure on the gas. If a container of nitrogen has a volume of litres with psi, what is the volume if the tank has a psi pressure.
- Calculate the volume to the nearest whole number.
- Use the given values and calculate the proportionality constant as well as required solution.
Step 1 of 2
Write the inversely proportionality relation between the volume and pressure of a gas in container.

Where volume is represented by v and pressure is represented by p.
Remove the proportionality and place a constant say k.

Substitute the given values of nitrogen that v=29.5 and
p=2000 and calculate the value of k from above equation.

Step 2 of 2
Substitute the value p=14.7 and above calculated k value in the equation

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation;
3*n-4-(14)=0
Pull out like factors :
3n - 18 = 3 • (n - 6)
Solve : 3 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solve : n-6 = 0
Add 6 to both sides of the equation :
n = 6
Answer:
B they are close together
Step-by-step explanation:
You simply switch the odds, the answer would be b:a
Answer:
D)The range of f(x) includes values such that y ≥ 1, so the domain of f–1(x) includes values such that x ≥ 1.
Step-by-step explanation:
The missing tables are:
First table
x: 0 1 2
f(x): 1 10 100
Second table
x: 1000 100 10
f^-1(x): 3 2 1
Option A is not correct because f(x) has a y-intercept at (0, 1)
If f(x) has a y-intercept, then f^-1(x) has a x-intercept, which is located at (1, 0). Then option B is not correct
Option C is not correct because the domain of f^-1(x) is associated with x values.
Option D is correct because the domain of f(x) is the range of f^-1(x) and vice versa