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blsea [12.9K]
3 years ago
6

find the volume of a cylinder with a diameter of 6 inches and a height that is three times the radius. use 3.14 for pi and round

your answer to the nearest hundereth
Mathematics
1 answer:
boyakko [2]3 years ago
5 0

Answer:

Step-by-step explanation:

answer is 55

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kenny6666 [7]
The answer is D, tony would always be behind Robert.
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A six-pack of soda costs $2.49, a 12-pack of soda costs $3.99, and a 24-pack of soda costs $5.49. Which pack has the lowest cost
vagabundo [1.1K]
The 24 pack. The 6 pack would be 41 cents per unit, the 12 would be 33, but the 24 would be 22. 
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3 years ago
Y=[[x]]<br> evaluate this function at x=3
dedylja [7]

Step-by-step explanation:

Solution

y=[[x]], at x=3,

therefore the function of y = 3

you can merge 3,3

7 0
3 years ago
Square root of 115 115/11 and 10.5624 from least to greatest
Mrac [35]
From least to greatest.  in this order  115/11  10.5624  115
8 0
3 years ago
Determine n between 0 and 19 such that (2311)(3912) ≡ n mod 20.
sleet_krkn [62]

You can write 2311 and 3912 in the form 20q+r:

2311=115\cdot20+11

3912=125\cdot20+12

Then

2311\cdot3912=(115\cdot20+11)(125\cdot20+12)

2311\cdot3912=115\cdot125\cdot20^2+(11\cdot125+12\cdot115)\cdot20+11\cdot12

Taken modulo 20, the terms containing powers of 20 vanish and you're left with

2311\cdot3912\equiv11\cdot12\equiv132\pmod{20}

We further have

132=6\cdot20+12

so we end up with

2311\cdot3912\equiv12\pmod{20}

and so n=12.

###

If instead you're trying to find 2311^{3912}\pmod{20}, you can apply Euler's theorem. We can show that \mathrm{gcd}(2311,20)=1 using the Euclidean algorithm. Then since \varphi(20)=8, and 8 divides 3912, we have

2311^{3912}\equiv2311^{489\cdot8}\equiv(2311^{489})^8\equiv1\pmod{20}

To show 2311 and 20 are coprime:

2311 = 115*20 + 11

20 = 1*11 + 9

11 = 1*9 + 2

9 = 4*2 + 1   =>  gcd(2311, 20) = 1

3 0
3 years ago
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