Answer:
1) 26
2) 6.5
the sum of numbers/ number of them
-12+-12=-24
-6+-6=-12
-11+-11=-22
-10+-10=-20
-9+-9=-18
-8+-8=-16
-7+-7=-14
-5+-5=-10
-4+-4=-8
-3+-3=-6
-1+-1=-2
1+1=2
2+2=4
3+3=6
4+4=8
5+5=10
6+6=12
Answer:
SA = 1,176 ft².
Step-by-step explanation:
To find the surface area of the triangular prism, we can solve for the rectangular base, both triangular faces, and lateral sides separately.
For the rectangular base: (Use formula l×w)
20 × 18 = 360 ft²
For the triangular faces: (Use formula 1/2(b·h)
1/2(18 × 12) = 108 ft²
Since there are two faces, we need to double the amount.
108 × 2 = 216 ft².
Finally, solve for the lateral sides:
20 × 15 = 300 ft².
There are two sides, so:
300 × 2 = 600 ft².
Add up all of these areas:
600 + 216 + 360 = 1,176 ft²
In base 10, the positional of each digit represents which power of 10 that position is taken to and the number represents how many of them you have, i.e. the number 532
100s, 10s, 1s
5.........3......2
Any other base works the same way but instead of powers of 10, we use whatever power that base is, so the number 25 in base 2:
16s, 8s, 4s, 2s, 1s
1.......1......0....0....1
To convert from base 10 to a different base, first find the highest power (position) in that base that is less than your numbers, you can do that by taking the log and round down (for the power) and take ithe base to that number (for the value). E.g. for the number 83, in base 2 you would do log2(83)=6 (rounded down), so that has the 2^6=64s place. Again with base 53, log3(83)=4, and is the 3^4= 81s place. (You can do log(83)/log(2)=6 if you can't change the base on your calculator).
So, starting with the highest you have just found, list all the powers of the base (just divide by the base each time), so base 2:
64s, 32s, 16s, 8s, 4s, 2s, 1s
Next you just go from highest to lowest, and, starting with your number, see how many of each position you can fit into it (keeping the number inside your base), subtracting the amount from it each time you do so. E.g. for base 2, number 83:
64s, 32s, 16s, 8s, 4s, 2s, 1s
1.........0.......1......0....0....1......1
83.....19......3.....3....3....1.....0
So 83 in base 2 is 1010011.
In base 3, for the number 140:
81s, 27s, 9s, 3s, 1s
1........2......0....1.....2
140..59......5...2....0
Starting at 140, 1 81 will fit into it so place a 1 in the 81s place and subtract 1*81 from 140 to get 59. 2 27s fit into 59 so write 2 under the 27s place and subtract 2*27=54 from 59 = 5. Continue and you should always end up with 0 remaining.
So 140 in base 3 is 12012.
I hope you understand this, it looks abit complicated at first but it's quite easy when you get the hang of it.
Answer:
D) 1/2(2x-6)=-6 = x = -3
Step-by-step explanation:
A. x = 3
B. x = 7/3
C. x = 4
D. x = -3
Solve for x:
(2 x - 6)/2 = -6
Hint: | Multiply both sides by a constant to simplify the equation.
Multiply both sides of (2 x - 6)/2 = -6 by 2:
(2 (2 x - 6))/2 = -6×2
Hint: | Cancel common terms in the numerator and denominator of (2 (2 x - 6))/2.
(2 (2 x - 6))/2 = 2/2×(2 x - 6) = 2 x - 6:
2 x - 6 = -6×2
Hint: | Multiply 2 and -6 together.
2 (-6) = -12:
2 x - 6 = -12
Hint: | Isolate terms with x to the left hand side.
Add 6 to both sides:
2 x + (6 - 6) = 6 - 12
Hint: | Look for the difference of two identical terms.
6 - 6 = 0:
2 x = 6 - 12
Hint: | Evaluate 6 - 12.
6 - 12 = -6:
2 x = -6
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of 2 x = -6 by 2:
(2 x)/2 = (-6)/2
Hint: | Any nonzero number divided by itself is one.
2/2 = 1:
x = (-6)/2
Hint: | Reduce (-6)/2 to lowest terms. Start by finding the GCD of -6 and 2.
The gcd of -6 and 2 is 2, so (-6)/2 = (2 (-3))/(2×1) = 2/2×-3 = -3:
Answer: x = -3
