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3 years ago

Plsss help i’ll give brainliest if you give a correct answer

Mathematics

2 answers:

ahrayia [7]3 years ago

4 0

Answer:

y=15

Step-by-step explanation:

Anestetic [448]3 years ago

4 0

Answer:

y=15

Step-by-step explanation:

To find y:

8y=120 –––Divide both sides by 8 so you can get y alone

y=15

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Please help: linear algebra problem. (Linear combinations)

DochEvi [55]

Answer:

$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

This tells us that:

$A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]$

$b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

$c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$ .

So we want to find a way to express this as:

Ax=b where x is the scalar vector, $\left[\begin{array}{ccc}c\\d\end{array}\right]$ .

So we can write this as:

$\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]$

3 0

3 years ago

Two thirds of a number is no more than -10

Aliun [14]

Let x be the number in the problem. When it states that x is "no more than -10", it means than it is less than or equal to -10. So, we have

$\frac{2}{3}$ x≤-10

In order to cancel out the $\frac{2}{3}$ on the left and isolate x, we multiply both sides by $\frac{3}{2}$ (since $\frac{3}{2}$ · $\frac{2}{3}$ =1). Thus, we have

x≤-10· $\frac{3}{2}$ =-15

Therefore, x≤-15

7 0

3 years ago

Please help

ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

$x^2+4y^2=100\\4y-x^2=-20$

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

$4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100$

Now we can solve for y:

$4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5$

So plugging in y = 4 into an equation and solving for x, we have:

$x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6$

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.

5 0

3 years ago

Hurry up need this answered quickly!

Naddik [55]

Answer:

26.3158 percent chance fraction is 500/19

Step-by-step explanation:

hope this helps

pls mark brainliest

fraction is 500/19

3 0

2 years ago

HELP ASAP Find the Difference. SHOW YOUR WORK 3x + 5 - (2x + 2)

REY [17]

Answer:

3x + 5 - (2x + 2)

3x + 5 -2x-2

x+3

Step-by-step explanation:

3 0

2 years ago