All categories

3 years ago

20+3×6= ?? Do you multiply first or add first?

Mathematics

1 answer:

Sonja [21]3 years ago

7 0

Answer: You should multiply first.

Step-by-step explanation:

Please- Parenthesis

Excuse- Exponent

My- Multiply

Dear-Divide

Aunt- Addition

Sally-Subtraction

Hopes this helps you should now know what order to use when solving linear expressions or any problem.

You might be interested in

Help me solve this problem 98+p=56

Arlecino [84]

p=-42

move 98 to the right side of the equal sign which becomes -98

p=56-98

do the math

p=-42

3 0

3 years ago

Read 2 more answers

Find the sum of 5x + 6 and -11x - 9

Setler79 [48]

-6x - 3
Step-by-step-explanation:

3 0

3 years ago

Help help help help help pleases pelass thank you

Elodia [21]

Answer:

a' (-6,7) b' (-5,3) c'(-2,4)

Step-by-step explanation:

5 0

2 years ago

Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

6 0

4 years ago

A semi-circle with a diameter of 6 cm sits on top of an isosceles trapezoid. Find the area of the entire figure.

dedylja [7]

Answer:

Step-by-step explanation:

8 0

2 years ago