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3 years ago

20+3×6= ?? Do you multiply first or add first?

Mathematics

1 answer:

Sonja [21]3 years ago

7 0

Answer: You should multiply first.

Step-by-step explanation:

Please- Parenthesis

Excuse- Exponent

My- Multiply

Dear-Divide

Aunt- Addition

Sally-Subtraction

Hopes this helps you should now know what order to use when solving linear expressions or any problem.

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7x - 32+9x-8+5x - 27=180 what’s x?

Nadya [2.5K]

Answer:

Fraction: x = 247/21

Decimal: 11.76

Mixed Number: 11 16/21

Step-by-step explanation:

Brainliest Please!!

4 0

2 years ago

Please help me!!

nikitadnepr [17]

its the first one

Step-by-step explanation:

because per pertains to to x

8 0

2 years ago

What is the formula for the area of a triangle?

SashulF [63]

The formula to find the area of a triangle is :

1/2 base*height

For instance:

base=4 cm

height=5cm

area of traingle=1/2*b*h

 =1/2*4*5

 =10cm^2

Hope it helps...

Good luck on your assignment

6 0

2 years ago

The volume of a tetrahedron is 1 6 of the volume of a parallelepiped whose sides are formed using the vectors coming out of one

Irina18 [472]

Answer: The volume of the tetrahedron is 2 units.

Step-by-step explanation:

Let A = (1, 1, 1)

B = (1, 5, 5)

C = (2, 2, 1)

The volume of a tetrahedron is given as

V = (1/6)|AB, AC, AD|

Where |AB, AC, AD| is the determinant of the matrix of AB, AC, AD.

We need to determine AB, AC, and AD

Suppose A = (a1, a2, a3)

B = (b1, b2, b3)

C = ( c1, c2, c3)

AB = ( b1 - a1, b2 - a2, b3 - a3)

Similarly for AB, AC, BC, etc.

AB = (1 - 1, 5 - 1, 5 - 1)

= (0, 4, 4)

AC = (1, 0, 2)

AD = (1, 1, 0)

Volume =

(1/6) |0 4 4|

|1 0 2|

|1 1 0|

= (1/6)[0(0 - 2) - 4(0 - 2) + 4(1 - 0)

= (1/6)(0 + 8 - 4)

= (1/6)(12)

V = 12/6 = 2 units

5 0

2 years ago

Given the following observed and expected data (total of 1000), using chi-squared calculate a p-value that corresponds with this

finlep [7]

Answer:

The answer is " $0.90>p>0.75.$ "

Step-by-step explanation:

$\text{Cinnabar vestigial} \ \ \ \ \ \ \ \ \ \ \ 384 \ \ \ \ \ \ \ \ \ \ \ 390 \ \ \ \ \ \ \ \ \ \ \ -6 36 \ \ \ \ \ \ \ \ \ \ \ 0.092308\\\\$

$roof \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 408 \ \ \ \ \ \ \ \ \ \ \ 390 \ \ \ \ \ \ \ \ \ \ \ 18 \ \ \ \ \ \ \ \ \ \ \ 324 \ \ \ \ \ \ \ \ \ \ \ 0.830769\\\\\text{Cinnabar vestigial roof} \ \ \ \ \ \ \ \ \ \ \ \ \ 63 \ \ \ \ \ \ \ \ \ \ \ \ \ 70\ \ \ \ \ \ \ \ \ \ \ \ -7 \ \ \ \ \ \ \ \ \ \ \ 49 \ \ \ \ \ \ \ \ \ \ \ 0.7\\\\\text{wild type} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 72 \ \ \ \ \ \ \ \ \ \ \ 70 \ \ \ \ \ \ \ \ \ \ \ 2 \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ 0.057143\\\\$

$vestigial \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 32 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.257143\\\\$

$\text{Cinnabar roof} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 34\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.028571\\\\\text{roof vestigial} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ -1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.2\\\\$

$\text{cinnabar} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.8 \\\\$

$Total \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1000 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 2.965934$

Eight phenotypes were present.

Df is provided also by a number of phenotypes -1 The degree of freedom

$\to df = 8-1= 7$

For p-value 0,9, Chi-square is 2.83;

The p-value of 0.75 is 4.5. Chi-square

Chi-sqaure value is observed at 2.965.

That means 0.90>p-value>0.75.

7 0

2 years ago