Hello : let : x the lenght y : the widith the perimeter is ; 2(x+y) and the area is : xy so the system : 2(x+y) =24 xy = 35 x+y = 12.....(1) xy = 35 ...(2) by (1) : y = 12-x subsct in (2) : (12-x)x = 35 x²-12x+35 = 0 (x-7)(x-5) = 0 x-7=0 or x-5 = 0 x=7 or x=5 if : x=7 y = 12-7 = 5 if : x=5 y = 12-5 =7 but : x<span> <span>><span> y </span></span></span>conclusion : one solution (7 , 5).