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Marat540 [252]
3 years ago
12

a customer went to a garden shop and bought some potting soil for $11.50 and 9 shrubs. the total bill was $94.75. write and solv

e an equation to find the price of each shrub. a. 9p 11.5p = $94.75; p = $4.62 b. 9p $11.50 = $94.75; p = $11.75 c. 9p $11.50 = $94.75; p = $9.25 d. 9(p $11.50) = $94.75; p = $5.00
Mathematics
2 answers:
Mrac [35]3 years ago
8 0
To answer this problem, let p be the price of each scrub. The total bill (t) is the sum of the price of the potting soil (s) and of the 9 scrubs (n). This is depicted in the equation,
                                 $11.50 + 9p = $94.75
The value of p from the equation is 9.25. Thus, each scrub costs $9.25. The answer is letter C.
Rama09 [41]3 years ago
8 0

Let

p---------> the price of each scrub

s----------> the price of the potting soil

T--------> total bill

we know that

T=9p+s

in this problem

T=\$94.75\\ s=\$11.50\\p=?

<u>substitute the values in the formula above </u>

\$94.75=9p+\$11.50

solve for p

9p=94.75-11.50

9p=83.25

p=9.25

therefore

<u>the answer is the option C</u>

\$94.75=9p+\$11.50

p=9.25


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Answer:

d. 0.303

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

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Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

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When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

In this question:

We want the probability of Sean having a greater income than Evan, which is the probability of the subtraction of Sean's income by Evan's income is greater than 0.

Distribution of the difference between Sean's and Evan's income:

Sean has mean 225, Evan 240. So

\mu = 225 - 240 = -15

Sean's standard deviation is of 25, Evan's of 15. So

\sigma = \sqrt{25^2+15^2} = 29.15

Probability that Sean will have a greater income than Evan in a randomly selected week:

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Z = \frac{X - \mu}{\sigma}

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5 0
3 years ago
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Similarly, to find the value of f(5), we just need to evaluate the function at x=5. In other words, we are going to replace x with 5 in the function:
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We can conclude that f(-7)=128 and f(5)=0.031
7 0
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