Question

Example 2

Answer 1

Answer:

$d =\frac{10}{3}t + 11$

Step-by-step explanation:

Given

Represent time with t and distance with d

The time at which he sets his timer is 0.

So:

$(t_1,d_1) = (0,11)$

After 3 seconds:

$(d_2,d_2) = (3,21)$

Required

Determine the linear equation

First, we need to determine the slope (m):

$m = \frac{d_2 - d_1}{t_2 - t_1}$

Substitute in, values

$m = \frac{21 - 11}{3 - 0}$

$m = \frac{10}{3}$

Next, we determine the equation sing

$d - d_1 = m(t - t_1)$

Where

$(t_1,d_1) = (0,11)$

$m = \frac{10}{3}$

$d - 11 =\frac{10}{3}(t - 0)$

$d - 11 =\frac{10}{3}t - 0$

$d - 11 =\frac{10}{3}t$

Add 11 to both sides

$d - 11+11 =\frac{10}{3}t + 11$

$d =\frac{10}{3}t + 11$

Hence, the linear equation is: $d =\frac{10}{3}t + 11$