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Taya2010 [7]
3 years ago
7

Define standard meter​

Physics
1 answer:
e-lub [12.9K]3 years ago
6 0

Answer:

the standard metre is the length of path travelled by light in vacuum during interval of time of a second

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how does the size of objects impact the pull of gravity between Earth and a baseball thrown into the air
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A bike rider approaches a hill with a speed of 8.5 m/s. The total mass of the bike rider is 91kg. What is the kinetic energy of
Anestetic [448]

a) The kinetic energy (KE) of an object is expressed as the product of half of the mass (m) of the object and the square of its velocity (v²):

KE = \frac{1}{2}m* v^{2}

It is given:

v = 8.5 m/s

m = 91 kg

So:

KE= \frac{1}{2}*91*8.5^{2} =3,287.4J


b) We can calculate height by using the formula for potential energy (PE):
PE = m*g*h

In this case, h is eight, and PE is the same as KE:
PE = KE = 3,287.4 J

m = 91 kg

g = 9.81 m/s² - gravitational acceleration

h = ? - height


Now, let's replace those:

3,287.4= 91 * 9.81 * h

⇒ h = 3,287.4/(91*9.81) = 3,287.4/892.7 = 3.7 m

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3 years ago
What are gamma rays and what are its uses??<br>​
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"Gamma rays" is the name that we call the shortest of all electromagnetic waves.  They're shorter than radio waves, microwaves, infrared waves, heat waves, visible light waves, ultraviolet waves, and X-rays.  They extend all the way down to waves that are as short as the distance across an atom.

Being so short, they carry lots of energy.  They can penetrate many materials, and they can damage living cells and DNA.  They're dangerous.

The sun puts out a lot of gamma radiation.  The atmosphere (air) filters out a lot of it, otherwise there couldn't even be any life on Earth.  

As soon as astronauts fly out of the atmosphere, they need a lot of shielding from gamma rays.

You know the precautions we take when we're around X-rays.  The same precautions apply around gamma rays, only a lot more so.

It's only in the past several years that we've learned how to MAKE gamma rays without blowing things up.  Also, how to control them, and how to use them for medical and industrial applications.

3 0
3 years ago
A train has an acceleration of magnitude 0.90 m/s2 while stopping. A pendulum with a 0.55-kg bob is attached to a ceiling of one
anygoal [31]

The angle of the pendulum with the vertical is 5.2^{\circ}

Explanation:

As the train decelerates, the bob of the pendulum will feel a force given by

F=ma

where

m = 0.55 kg is the mass of the bob

a=0.9 m/s^2 is the magnitude of the acceleration

In the horizontal direction.

The pendulum will be inclined at an angle \theta from the vertical, so it will be in equilibrium, and therefore the horizontal component of the tension in the string must be equal to the net force F of the previous equation:

T sin \theta = ma (1)

where T is the tension in the string.

We also know that the bob is in equilibrium along the vertical direction: so the vertical component of the tension must be equal to the weight of the bob,

T cos \theta = mg (2)

where g=9.8 m/s^2 is the acceleration of gravity.

Dividing eq.(1) by eq(2), we get:

tan \theta = \frac{a}{g}

And therefore, we find the angle:

\theta=tan^{-1}(\frac{a}{g})=tan^{-1}(\frac{0.90}{9.8})=5.2^{\circ}

Learn more about forces and acceleration:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

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3 years ago
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