Answer:
The man's velocity relative to the moving walkway is, v₂₃ = 0.2 m/s
Explanation:
Given data,
The speed of the moving walkway, v₁₂ = 0.9 m/s
The speed of the man walking on a walkway to the stationary observer, v₁₃ = 1.1 m/s
The speed of the man walking on a walkway to the walkway, v₂₃ = ?
The formula for relative velocity is,
<em> v₁₃ = v₁₂ + v₂₃</em>
∴ v₂₃ = v₁₃ - v₁₂
Substituting the values,
v₂₃ = 1.1 - 0.9
= 0.2 m/s
Hence, the man's velocity relative to the moving walkway is, v₂₃ = 0.2 m/s
Answer:
Slader
Explanation:
please mark as brainliest
This problem is asking for the required heat to change the temperature of 500 g of water by 50 °C. At the end, the result turns out to be 25,000 cal as shown below:
<h3>Calorimetry</h3>
In science, calorimetry is the process whereby objects lose or gain energy according to the decrease or increase of their temperature. Thus, for these problems, we need to use the following equation:
Where Q stands for the heat, m for the mass, C for the specific heat of the object and T for the temperature (final and initial). Thus, for this problem, since it is about water, one fixes its specific heat as 1 cal /(g-°C) in order to obtain the following:
Learn more about calorimetry: brainly.com/question/1407669
More info? I think the question is incomplete. Although, I believe the first 2 blanks are "rises"