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Andre45 [30]
2 years ago
5

What are the solutions to the equation 3x²+15x=18​

Mathematics
2 answers:
ANEK [815]2 years ago
8 0
X=-6
that’s what i got
lmk if it’s correct
mixer [17]2 years ago
7 0

Answer:

x = 1 or x = −6

Step-by-step explanation:

Step 1: Subtract 18 from both sides.

3x2+15x−18=18−18

3x2+15x−18=0

Step 2: Factor left side of equation.

3(x−1)(x+6)=0

Step 3: Set factors equal to 0.

x−1=0 or x+6=0

x=1 or x=−6

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Solve the following quadratic equation 3x²-8x+5=0<br>​
nekit [7.7K]

To solve this equation, let's factor the left side.

Although you can factor it in different ways, I will show you a trick.

First, forget about the 3 and we have x² - 8x + 5.

Now, multiply the 3 by the constant to get 15.

So we have x² - 8x + 15.

Now factor to get (x - 5)(x - 3).

Now divide each of the constants in the

binomials by the leading coefficient, 3.

So we have (x - 5/3)(x - 3/3).

Simplify to get (x - 5/3)(x - 1).

Now move any denominators in front of the x in the binomial.

Moving the 3 in front of the x, we have 3x.

So our answer is (3x - 5)(x - 1) = 0.

So either 3x - 5 = 0 or x - 1 = 0.

Solving from here, we get x = 5/3 or x = 1.

8 0
3 years ago
A cake recipe calls for 3/4 cup of flour for every 1/3 teaspoon of baking powder. What is the unit rate of cups per teaspoon?
Aliun [14]

Answer:

i just looked it up and i saw 57 so i think thats it

Step-by-step explanation:

6 0
3 years ago
Can someone help with this question
Zielflug [23.3K]

Answer:

<1= 60

<2=120

<3=60

<4=60

<5=120

<6=120

<7=60

Step-by-step explanation:

6 0
2 years ago
Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -
rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by  D and its formula is

D=b^2-4ac\\

Where

a= the coefficient of the x^{2}

b= the coefficient of x

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant  and evaluate our answer accordingly .

Let us start with

y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\

Hence we have two real roots for this equation.

y = 2x^2 - 6x + 5\\

y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D

Hence we do not have any real root for this quadratic

y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\

Hence D>0 and thus we have two real roots for this equation.

y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\

Hence we have one real root to this quadratic equation.

7 0
2 years ago
Find the value of w to make the statement true.<br>-w = -10 + 4w
Alinara [238K]
Move variable to the left. -w= -10+ 4W
-w-4W =-10
Collect like terms
-5w=-10 divide both sides by 5
8 0
3 years ago
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