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brilliants [131]
3 years ago
13

Simplify and write the trigonometric expression in terms of sine and cosine:

Mathematics
1 answer:
asambeis [7]3 years ago
4 0

Answer:

we have the expression as;

1/sin u cos u

Step-by-step explanation:

tan u = sin u/cos u

cot u = cos u/sin u

Thus;

sin u/cos u + cos u/sin u

The lcm is sin u cos u

Thus, we have that;

(sin^2 u + cos^2 u)/sin u cos u

But ; sin^2 u + cos^2 u = 1

so we have ;

1/sin u cos u

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B = 10 feet area = 35 feet 2 Find the height of the triangle.
Alexandra [31]

Answer:

Height is 7m

Step-by-step explanation:

B = 10 feet area = 35 feet 2 Find the height of the triangle.

Area of triangle = 1/2 b×h

35 = 1/2(10×h)

35 × 2 = 10h

70 = 10h

h = 70/10

h = 7m

8 0
4 years ago
Lawrence buys his friends candy in the morning for $3 a box, but forgot some of his friends, so he went back to the candy shop a
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3 • t + 6 • t = the amount he spent
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Which intervals are most appropriate for a histogram
Lorico [155]

Answer:

C. 10–15, 15–20, 20–25, 25–30, 30–35

Step-by-step explanation:

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3 years ago
Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ​ ,0)(, plus minus, square root o
Alchen [17]

Answer:

The equation of ellipse centered at the origin

\frac{x^2}{18} +\frac{y^2}{10} =1

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)  

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are c^2=a^2-b^2

      a^{2} = c^{2} +b^{2}

a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}

a^{2} =18

a=\sqrt{18}

The equation of ellipse formula

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

we know that a=\sqrt{18} and b=\sqrt{10}

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u />\frac{x^2}{18} +\frac{y^2}{10} =1<u />

                                   

8 0
3 years ago
Read 2 more answers
Solve using the quadratic frmula 2x^2-5x=3
Mnenie [13.5K]

2x2−5x=3

I think the first step would be to

Subtract 3 from both sides

2x2−5x−3=3−3

2x2−5x−3=0

Then

For this equation: a=2, b=-5, c=-3

2x2+−5x+−3=0

Lastly you would

Use quadratic formula with a=2, b=-5, c=-3

I think your answer would then have to be...

x = 3 or x =  −1 /2

4 0
3 years ago
Read 2 more answers
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