Answer:
97.53 in³
Step-by-step explanation:
The cylindrical birthday cake has a diameter (d) of 14 inches and a height (h) of 6 inches.
The radius of the cake (r) = diameter / 2 = 14 inches / 2 = 7 inches.
The volume of the full cake = πr²h = π(7²)6 = 924 in³
Since only a part of the cake was cut and given to Myong. The total measure of the cake is 360°, but the part given to her was 38°. Hence the volume of her slice is given as:
Volume of her slice = (38 / 360) * volume of the full cake = (38 / 360) * 924 = 97.53 in³
Volume of her slice = 97.53 in³
Answer:
Step-by-step explanation:
mean = total / amount of numbers
= 15/5 = 3
median = 4 middle number
mode = most common numbers = 3,2
The next larger whole number is 638 .
The next smaller whole number is 637 .
637.892 is closer to 638 than it is to 637 .
The nearest whole number is 638 .
Answer: 18 units
Step-by-step explanation:since its is a horizontal line x2 - x1
7 -1 = 6
line 2:
since this is a vertical line y2 - y1
7 - 3 = 4
line 3:
since this is a horizontal line x2 - x1
7 - 4 = 3
line 4:
for this we need to use the distance formula which allows us to find the distance making a third point to form a right angle triangle
point 1: (1,3)
point 2: (4,7)
point 3 (new point) : (4,3)
now we can apply the pythogorean thereum (C squared = B squared + A squared) with the following lines.
line 1: (1,3) - (4,7)
line 2: (1,3) - (4,3)
line 3: (4,3) - (4,7)
line 1 squared = line2 squared + line 3 squared
calculate length of line 2 and 3
line 1 squared = (4 - 1) squared + (7 - 3) squared
line 1 squared = 3 squared + 4 squared
line 1 squared = 9 + 16
line 1 squared = 25
root both sides
line 1 = 5
add all the liens together
6 + 4 + 3 + 5 = 18
Answer:
Step-by-step explanation:
My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.
