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satela [25.4K]
3 years ago
6

Find the area Square root of 3 and square root of 75

Mathematics
2 answers:
antoniya [11.8K]3 years ago
8 0

Answer:0.2

Step-by-step explanation:

Combine

√

3

and

√

75

into a single radical.

√

3

75

Cancel the common factor of

3

and

75

.

Tap for more steps...

√

1

25

Rewrite

√

1

25

as

√

1

√

25

.

√

1

√

25

Any root of

1

is

1

.

1

√

25

Simplify the denominator.

1

5

The result can be shown in multiple forms.

Exact Form:

1

5

Decimal Form:

0.2

inn [45]3 years ago
4 0
I think it’s 0.2 sorry if I’m wrong
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If mrs. rodriguez eats 14 crackers a day. how many crackers will she eat in 3 weeks?
solong [7]
14 x 7=98
98 x 3= 294
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3 years ago
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Reduce 3/3 x 6/12 to the lowest form
Burka [1]
3/3 is basically 1
6/12 is simplified down to 1/2
1 x 1/2 = 1/2

ANSWER - 1/2
6 0
3 years ago
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PLZZZ HELPPP THIS IS DUE!!
allochka39001 [22]

Answer:

y=3x-2..... i

x-y=4...... ii

x-4=y

Substituting the value of y in equation i,

x-4=3x-2

2-4=3x-x

-2=2x

x=-1.

From ii,

-1-4=y

y=-5.

x=-1, y=-5

Step-by-step explanation:

brainest please

7 0
4 years ago
At a large Midwestern university, a simple random sample of 100 entering freshmen in 1993 found that 20 of the sampled freshmen
guajiro [1.7K]

Answer:

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

p1 -> 1993

20 out of 100, so:

p_1 = \frac{20}{100} = 0.2

s_1 = \sqrt{\frac{0.2*0.8}{100}} = 0.04

p2 -> 1997

10 out of 100, so:

p_2 = \frac{10}{100} = 0.1

s_2 = \sqrt{\frac{0.1*0.9}{100}} = 0.03

Distribution of p1 – p2:

p = p_1 - p_2 = 0.2 - 0.1 = 0.1

s = \sqrt{s_1^2+s_2^2} = \sqrt{0.04^2 + 0.03^2} = 0.05

Confidence interval:

p \pm zs

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.  

The lower bound of the interval is:

p - zs = 0.1 - 1.645*0.05 = 0.01775


The upper bound of the interval is:

p + zs = 0.1 + 1.645*0.05 = 0.18225


The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

6 0
3 years ago
make the indicated conversion assume a 360-day year as needed,8months to simplified fraction of a year
balandron [24]
<span>8 months to simplified fraction of a year:

There are 12 months in a year.

8 month = 8/12 = 2/3</span>
6 0
3 years ago
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