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tia_tia [17]
3 years ago
13

How many moles are in 23 g of LICI

Chemistry
1 answer:
Leya [2.2K]3 years ago
6 0

Answer:

42.394

Explanation:

trust me lol

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If the Earth is at a perpendicular angle or right angle to the sun we will be experiencing...??
snow_tiger [21]

Answer:

angle

Explanation:

let us see the sun moves an a angle

5 0
3 years ago
What is one way to create a negative ion?
san4es73 [151]

Answer:

Burn beeswax candles. They clean the air, produce negative ions, and assist with allergy and asthma reduction. Run an indoor water fountain. The force or energy of falling water causes the neutral particles in air to split which frees electrons to attach to other air molecules resulting in negative ions.

Explanation:

8 0
3 years ago
In what circumstance would the complete and net ionic equations for a reaction be identical?
Yakvenalex [24]

Answer: Complete ionic equations dissociate all aqueous solutions into ions. Net ionic equations show the change that occurs in chemical reactions and do not show spectator ions that are the same in reactants and products. (b) If no spectator ions were present then complete and net ionic equations would be identical.

Explanation:

8 0
3 years ago
Calculate ΔH⁰298 (in kJ) for the process P(s) + 5/2 Cl2(g) → PCl5(g) from the following information.
Viefleur [7K]

Answer:

\Delta H_{298}^{0} for the process is -375 kJ

Explanation:

  • Given reaction is a combination of the two given elementary steps.
  • Summation of change in standard enthalpy (\Delta H_{298}^{0})of the two elementary reactions give \Delta H_{298}^{0} of the reaction P(s)+\frac{5}{2}Cl_{2}(g)\rightarrow PCl_{5}(g).

P(s)+\frac{3}{2}Cl_{2}(g)\rightarrow PCl_{3}(g)......\Delta H_{1}=-287kJ

PCl_{3}(g)+Cl_{2}(g)\rightarrow PCl_{5}(g)......\Delta H_{2}=-88kJ

-----------------------------------------------------------------------------------------------------

P(s)+\frac{5}{2}Cl_{2}(g)\rightarrow PCl_{5}(g)

\Delta H_{298}^{0} = \Delta H_{1}+\Delta H_{2}=-287kJ-88kJ=-375kJ

3 0
4 years ago
Homes may be heated by pumping hot water through radiators. What mass of water will provide the same amount of heat when cooled
dolphi86 [110]

Answer:

mass of water is 7.43 g

Explanation:

q = mc∆T

qsteam = 100 g × 1.864 J/(g °C) × (110 – 100) °C = 1864 J

qwater = mwater× 4.184 J/(g °C) × (95 – 35) °C = mwater× 251.04 J/g = qsteam = 1864 J

mwater = 1864 J / 251.04 J/g = 7.43 g

3 0
3 years ago
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